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Paha777 [63]
2 years ago
9

Complete the steps in solving 4/9=x/36

Mathematics
1 answer:
Whitepunk [10]2 years ago
3 0

Isolate the x. Note the equal sign. What you do to one side, you do to the other.

Cross multiply

(4/9)(9)(36) = (x/36)(36)(9)

(4)(36) = (x)(9)

Simplify

144 = 9x

Isolate the x. Divide 9 from both sides

144/9 = 9x/9

x = 144/9

x = 16

16 is your answer

hope this helps

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Solve the following systems of equations without graphing <br> 5x + 10y = 30<br> -5x +15y = 20
galben [10]

Answer:

(2, 2)

Step-by-step explanation:

In this case, elimination would be the most efficient means of solving.

Simply, add the two equations, and you will be left with only one variable to solve for. (In this case y) You are then able to take your solution and plug it into an equation and solve for x, therefore giving you their intercept.\

5x + 10y = 30

+

-5x + 15y = 20

(x's cancel) 25y = 50

25y = 50

y = 2

5x + 10(2) = 30

5x + 20 = 30

5x = 10

x = 2

The solution to this equation is (2, 2)

8 0
2 years ago
In tests of a computer component, it is found that the mean time between failures is 937 hours. A modification is made which is
VladimirAG [237]

Answer:

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Test Statistics z = 2.65

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

P- value = 0.004025

Step-by-step explanation:

Given that:

Mean \overline x = 960 hours

Sample size n = 36

Mean population \mu = 937

Standard deviation \sigma = 52

Given that the mean  time between failures is 937 hours. The objective is to determine if the mean time between failures is greater than 937 hours

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Degree of freedom = n-1

Degree of freedom = 36-1

Degree of freedom = 35

The level of significance ∝ = 0.01

SInce the degree of freedom is 35 and the level of significance ∝ = 0.01;

from t-table t(0.99,35), the critical value = 2.438

The test statistics is :

Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}

Z = \dfrac{960-937 }{\dfrac{52}{\sqrt{36}}}

Z = \dfrac{23}{8.66}

Z = 2.65

The decision rule is to reject null hypothesis   if  test statistics is greater than  critical value.

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

The P-value can be calculated as follows:

find P(z < - 2.65) from normal distribution tables

= 1 - P (z ≤ 2.65)

= 1 - 0.995975     (using the Excel Function: =NORMDIST(z))

= 0.004025

6 0
3 years ago
A. y=82x + 998<br> b. y=247.7x - 335<br> c. y=743x - 1647<br> d. y=998x + 82
MrMuchimi
A is the answer for the question
3 0
3 years ago
Read 2 more answers
Can someone solve this problem?
sashaice [31]

Answer: 55°

Step-by-step explanation: Let me know if you need an explanation.

4 0
3 years ago
Read 2 more answers
(20 Points) <br><br><br> Perform the indicated operations.
JulijaS [17]

Answer:

5x-8/12y

Step-by-step explanation:

x+1

3y

+

x−2

4y

−(

x+3 /6y

=

30xy2−48y2

72y3

=

30x−48/72y

=

5x−8 /12y

7 0
3 years ago
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