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Luda [366]
3 years ago
5

Lightning travels much faster than thunder so lightning is seen before thunder is heard. Using inductive reasoning and graph if

you count 45 s between the lightning and thunder how far away is the storm?

Mathematics
2 answers:
snow_tiger [21]3 years ago
7 0

Answer:

9 miles

Step-by-step explanation:

If you count the number of seconds between the flash of lightning and the sound of thunder, and then divide by 5, you'll get the distance in miles to the lightning:

5 seconds = 1 mile

45 ÷ 5 = 9 miles away

Alchen [17]3 years ago
5 0

Answer:

9 seconds.

Step-by-step explanation:

On your graph, use a ruler and your eye to get the best fitting line.  

Then find the time in seconds (45) which is between 40 and 50 on the x axis.

Go across to the y axis. You will find it is about 9 seconds.

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Factor 3y^2 - 4y. plzzzzzz
Lisa [10]

Answer:

y(3y - 4)

Step-by-step explanation:

3y^{2} -4y

Both have y.

Factor y out of 3y^{2} -4y

y(3y-4)

7 0
4 years ago
A new battery's voltage may be acceptable (A) or unacceptable (U). A certain flashlight requires two batteries, so batteries wil
klio [65]

Answer:

The probability that you test exactly 4 batteries is 0.0243.

Step-by-step explanation:

We are given that a new battery's voltage may be acceptable (A) or unacceptable (U). A certain flashlight requires two batteries, so batteries will be independently selected and tested until two acceptable ones have been found.

Suppose that 90% of all batteries have acceptable voltages.

Let the probability that batteries have acceptable voltages = P(A) = 0.90

So, the probability that batteries have unacceptable voltages = P(U) = 1 - P(A) = 1 - 0.90 = 0.10

Now, the probability that you test exactly 4 batteries is given by the three cases. Firstly, note that batteries will be tested until two acceptable ones have been found.

So, the cases are = P(AUUA) + P(UAUA) + P(UUAA)

This means that we have tested 4 batteries until we get two acceptable batteries.

So, required probability = (0.90 \times 0.10 \times 0.10 \times 0.90) + (0.10 \times 0.90 \times 0.10 \times 0.90) + (0.10 \times 0.10 \times 0.90 \times 0.90)

     =  0.0081 + 0.0081 + 0.0081 = <u>0.0243</u>

<u></u>

Hence, the probability that you test exactly 4 batteries is 0.0243.

3 0
3 years ago
What is limit of (startstartfraction negative sine (startfraction pi x over 3 endfraction) overover 3 endendfraction) as x appro
Nutka1998 [239]

I'm guessing your limit is

\displaystyle \lim_{x\to5} \frac{-\sin\left(\frac{\pi x}3\right)}3

The limand is continuous at x = 5, so we can evaluate the limit directly by substituting x = 5:

\displaystyle \lim_{x\to5} \frac{-\sin\left(\frac{\pi x}3\right)}3 = -\frac13 \sin\left(\frac{5\pi}3\right) = -\frac13 \times \left(-\frac{\sqrt3}2\right) = \boxed{\frac1{2\sqrt3}} = \boxed{\frac{\sqrt3}6}

7 0
2 years ago
A grid shows the positions of a subway stop and your house. The subway stop is located at (7, -6) and your house is located at (
Westkost [7]
\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ 7}}\quad ,&{{ -6}})\quad &#10;%  (c,d)&#10;&({{ -9}}\quad ,&{{ 5}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}&#10;\\\\\\&#10;d=\sqrt{[-9-7]^2+[5-(-6)]^2}\implies d=\sqrt{[-9-7]^2+[5+6]^2}
5 0
4 years ago
Product of two consecutive integers is 29 more than their sum . Find the integers
geniusboy [140]
Product of two consecutive integers is:

n(n+1)=n²+n

Sum of two consecutive integers is:

n+(n+1)=n+n+1=2n+1

What you have proclaimed:

n²+n=2n+1+29

n²+n=2n+30

n²+n-2n-30=0

n²-n-30=0

(n-6)(n+5)=0

Therefore n=6 or n=-5.

When n=6,

n+1=7

First answer: 6 and 7.

-----------------------------

When n=-5,

n+1=-4

Second answer: -4 and -5.
6 0
3 years ago
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