The answer would be C because you wouldn't know the angles yet.
Answer:
This is a geometric sequence because any term divided by the previous term is a constant called the common ratio. r=36/18=18/9=2 A geometric sequence is expressed as
\begin{gathered}a_n=ar^{n-1},\text{ where a=initial term, r=common ratio, n=term number}\\ \\ a_n=9(2^{n-1})\\ \\ a_6=9(2^5)\\ \\ a_6=288\end{gathered}an=arn−1, where a=initial term, r=common ratio, n=term numberan=9(2n−1)a6=9(25)a6=288
Answer:
If the bolt is .52, it is between .517 and .583, so it can go in the package.
Step-by-step explanation:
The first step is to determine what the error amount is
6% of .55
.06*.55 =.033
The bolt must be within .033 of .55
.55 - .033 = .517
.55 + .033 = .583
The bolt must be between .517 and .583 inches
If the bolt is .52, it is between .517 and .583, so it can go in the package.
Answer:
Option 3) y = 3x+1
Step-by-step explanation:
<u><em>Given equation is:</em></u>
y = 
Perpendicular => <u><em>It will have a slope of negative reciprocal to this slope</em></u>
So the ⊥ line has a slope = m = 3
Now,
Point = (x,y) = (1,4)
So, x = 1, y = 4
<u><em>Putting this in slope intercept form to get b</em></u>
=> 
=> 4 = (3)(1) + b
=> b = 4-3
=> b = 1
<u><em>Now, Putting m and b in the slope intercept form to get the required equation:</em></u>
=> y = 3x+1
Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
