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Jobisdone [24]
3 years ago
5

Which of the following is a solution of x^2 - 2x = -8?

Mathematics
1 answer:
Zina [86]3 years ago
6 0
X^2-2x=-8  add 1 to both sides

x^2-2x+1=-7  now the left side is a perfect square

(x-1)^2=-7  take the square root of both sides

x-1=±√-7  add 1 to both sides

x=1±√-7 which is

x=1±i√7  so

x=1+i√7 and 1-i√7
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Simplify 4x + 8y - 3x + 2y
mezya [45]

Answer: 4x-3x, and 8y+2y. x+10y is the equation in simplest form.

Step-by-step explanation:

Step 1. You need to combine like terms:

 4x-3x, and 8y+2y. x+10y would make the equation( 4x + 8y - 3x + 2y) in simplified form.

Hope I could help! :)

7 0
3 years ago
Read 2 more answers
Assume that the probability of any newborn baby being a girl is one half
asambeis [7]

Answer:

1/32

Step-by-step explanation:

P(0 girls)

= P(5 boys)

= (1 − ½)⁵

= 1/32

7 0
4 years ago
A jar contains n nickels and d dimes. There are 28 coins in the jar,and total value of the coins is $2.20. How many nickels and
Harman [31]
N + d = 20 (there are a total of 20 nickels and dimes).05n + .1d = 1.4 (total change equals $1.40)
7 0
3 years ago
13. The least common multiple of two non-zero integers a and b is the unique positive integer m such that (i) m is a common mult
Vlad [161]

Answer:

[a,b] divides n

Step-by-step explanation:

Let us denote the least common multiple of a and b [a,b]=m.

We want to prove that m divides n, where n is a multiple of a and b.

We suppose m does not divide n, then by the Division Theorem, there exists q and r integers such that:

(1) ... n=mq+r, where 0<r<m

As n is a multiple of a and b, there exists s and t integers such that:

sa=n and tb=n

Same thing happens to m as it is the least common multiple, there exists u and v such that:

ua=m and vb=m

So (1) has the following form:

n=mq+r ⇒ sa=uaq+r ⇒sa-uaq=r⇒(s-uq)a=r and

n=mq+r ⇒ tb=vbq+r ⇒ tb-vbq=r⇒ (t-vq)b=r

So r is a multiple of a and b, but r<m which is a contradiction as, m is the least common multiple of a and b. So this concludes the proof.

So this means that \frac{ab}{m} is and integer.

As m= vb, then \frac{m}{b} is an integer, lets say \frac{m}{b}=v; and as m=ua, then \frac{m}{a}=u.

So \frac{ab}{m}v=\frac{ab}{m}\frac{m}{b}=a, so \frac{ab}{m} divides a; on the other hand, \frac{ab}{m}u=\frac{ab}{m}\frac{m}{a}=b, so \frac{ab}{m} divides b. From this we can conclude that \frac{ab}{m} is a common divisor of a and b.

4 0
3 years ago
What is" a number minus 5 is 21"
Aleks [24]

Answer:

26

Step-by-step explanation:

just add 21 plus 5 then

4 0
3 years ago
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