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kykrilka [37]
3 years ago
14

The figure is a square. it's diagonals meet to form four right angles. what is the approximate value of x ?

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
5 0
The answer is 5.7 to your problem

Anettt [7]3 years ago
3 0

<u>Answer-</u>

<em>The approximate value of x is </em><em>5.7</em>

<u>Solution-</u>

<u>Properties of diagonals of square</u>

  1. The diagonals of a square bisect each other and meet at 90°
  2. The diagonals of a square bisect its angles.
  3. The diagonals of a square are equal.

The converse of 1st property is that if the diagonals meet at right angles, then the quadrilateral must be a rhombus or square. As in this case, each bisected diagonals are of same length, so it must be a square.

From the diagram, applying Pythagoras Theorem,

\Rightarrow x^2+x^2=8^2

\Rightarrow 2x^2=64

\Rightarrow x^2=32

\Rightarrow x=\sqrt{32}

\Rightarrow x=5.65\approx 5.7

Therefore, the approximate value of x is 5.7

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