M=(y2-y1)/(x2-x1)
=[-1-(-4)] / (3-1)
=(-1+4) / 2
=3/2
The probability is 0.08.
The probability that the first roll is a 4 is 1/6, since there is one 4 out of six total possibilities.
The probability that the second roll is an even number is 3/6, since there are 3 even numbers out of 6 possibilities.
Together, we have 1/6(3/6) = 3/36 = 0.08
I’d say 5cm 7cm 5cm because it all multiples to 175cm.
We have that Probability of having 5 is
From the Question we are told that
The probability that 5 will come up at least once
Generally the equation for the is mathematically given as
The sample space is
n=12
Therefore Probability of having 5 is

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It would be -7 hope this helps