Answer: 1/8x
Step-by-step explanation:
y= 1/8x
below are the x:y relationships
x:y
4:0.5
8:1
12: 1.5
16:2
20:2.5
24:3
28:3.5
32:4
etc.
The volume of a cylinder is
V=hpr^2 in this case h=40, r=20/2=10, and we will approximate pi as 3.14 so:
V=40(3.14)(10^2)
V=12560 ft^3
Answer:
373.8mmHg
Step-by-step explanation:
a =height (in km) above sea level,
the pressure P(a) (in mmHg) is approximated given as
P(a) = 760e–0.13a .
To determine the atmospheric pressure at 5.458 km, then we will input into the equation
P(5.458km) = 760e–0.13a .
= 760e^(-0.13×5.458)
=760e^-(0.70954)
= 760×0.4919
=373.8mmHg
Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg