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attashe74 [19]
3 years ago
12

$3500 deposit earning 6.75% compounded monthly, after 6 months

Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

3.619.80

          A=3500×1.005625 to the 6th power       A=3500×1.034228.                              

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Lakiesha is an employee who drives a 2019 Buick Verano as a company car. The fair-market value of the car is $28,545. She has be
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Answer:

Lease value          

Step-by-step explanation:

The lease value may bed defined as an open market capital valuation of the parts of the subject or the subject that are to be leased in regards of the terms of the lease.

In the context, Lakiesha drives a company car whose value is $ 7,750 according to 15-b publication. The car was available for 200 days in a year. She drove the car for 4500 miles for her personal use and 21250 miles in total. The fuel is paid by the employer. So here the best method that will yield the lowest fringe benefit amount for her is the lease value method.

3 0
3 years ago
Round 47.6001 to the nearest thousandth_______.
irakobra [83]
47.60<u>0</u>1
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5 0
3 years ago
A scuba diver is positioned at -30 feet. How many feet will she have to rise to change the position to -12 feet?
marshall27 [118]

Answer: 18

Step-by-step explanation:

5 0
3 years ago
Estimate 1 13 cos(x2) dx 0 using the Trapezoidal Rule and the Midpoint Rule, each with n = 4. (Round your answers to six decimal
babunello [35]

Answer:

(a) 4.152698

(b) 3.215557

Step-by-step explanation:

(a)

\int\limits^{13}_1 {cos(x^2)} \, dx =M_n=$\sum_{n=1}^{\infty} f(m_i)\Delta x $

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

Now, the midpoints of these subintervals are:

\frac{1+5}{2} =3\\\\\frac{5+9}{2} =7\\\\\frac{9+13}{2} =11

Hence:

M_4= 3*(cos(3^2))+3*(cos(7^2))+3*cos((11^2))\approx 4.152698

(b)

\int\limits^{13}_1 {cos(x^2)} \, dx =T_n=\frac{\Delta x}{2} (f(x_o)+2f(x_1)+2f(x_2)+...+2f(x_n_-_1)+f(x_n))

n=4, so :

Each subinterval has length :

\Delta x= \frac{b-a}{n} =\frac{13-1}{4} =\frac{12}{4} =3

Therefore the subintervals consist of:

[1,5], [5,9], [9,13]

The endpoints of the subintervals consist of:

5,9

Hence:

T_4= \frac{3}{2}(cos(1^2)+2*cos(5^2)+2*cos(9^2)+cos(13^2)) \approx 3.215557

8 0
3 years ago
quadriliteral DEFG has verticles at D(1,0), E(-2-2) F(2,4) and G(6-3) find the verticles of DEFG after a translation of 4 units
Svetlanka [38]
D (5, -5)
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If you need an explanation as to how I did, you just add 4 to the x coordinate and subtract 5 from the y coordinate since going down is negative.
8 0
3 years ago
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