Using the normal distribution relation, the probability that sample will exceed the weight limit is 0.004
<u>Using the relation</u> ::
The mean, μ = np = (162 × 19) = 3078
The standard deviation, σ = 28 × √19 = 122.049
<u>The Zscore</u> :
Zscore = (3401 - 3078) ÷ (122.049)
Zscore = 2.65
Hence,
P(Z > 2.65) = 1 - P(Z < 2.65)
Using a normal distribution table :
P(Z > 2.65) = 1 - 0.9959
P(Z > 2.65) = 0.004
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12/84 = 1/7 ≈ 0.14
The discount rate was 14%
Answer:
(x+1)(2x2−x+6)
Step-by-step explanation:
Answer:
4.1 x 10^-2
Step-by-step explanation:
Answer:
-x + 18
Step-by-step explanation:
just add 16 and 2. this is the furthest it can be simplified
