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Margaret [11]
3 years ago
10

Please help me I do not understand :(

Mathematics
2 answers:
Liula [17]3 years ago
8 0

Answer:

1. trapezoid

3. yes, just draw two random right angles and then make them intersect lol

4. rectangle, perimeter of 30

5. no, 3 right angles will equal 4

kvv77 [185]3 years ago
4 0

Answer:

Step-by-step explanation:

1. trapezoid

2. no not possible lol how do you even do that lol a square has only 90 degree angles and then an obtuse angle pops in no doesn't happen

3. yes just draw two random right angles and then make them intersect lol

4. rectangle, perimeter of 30

5. no

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2. A cookie recipe calls for 2 cups of brown sugar and 3 cups of flour. If a baker increases the recipe and uses 12 cups of flou
JulijaS [17]
12 cups of flour is 4 times the quantity in the recipe, so 4 times as much brown sugar is needed, 4×2=8 cups of brown sugar.
6 0
4 years ago
Read 2 more answers
Solve 20x+5y=15 for y
nexus9112 [7]
20x + 5y = 15

Subtract 20x on both sides

5y = 15 - 20x

Divide by 5 on both sides

y = 3 - 4x
8 0
4 years ago
I need to set up a 2 column proof for this problem.
dalvyx [7]

they are parallel to each other so find it out from there

8 0
3 years ago
Can somebody help me please ​
vesna_86 [32]

9514 1404 393

Answer:

  • 3n+6 (n = smallest)
  • 3n (n = middle)

Step-by-step explanation:

The usual method for doing this is to let n represent the smallest one. Then the three integers are ...

  n, n+2, and n+4

and their sum is ...

  (n) +(n+2) +(n+4) = 3n+6 . . . . sum of 3 consecutive odd integers (n = smallest)

_____

Personally, for consecutive number problems, I prefer to let the variable represent the average value. If n is the average value of 3 consecutive odd integers, is is the middle integer. Of course, the sum will be 3 times the average:

  (n-2) +(n) +(n+2) = 3n . . . . sum of 3 consecutive odd integers (n = middle one)

4 0
3 years ago
The sum of 3 consecutive odd numbers is 51. What is the value of the largest number?​
love history [14]
X, x+2, and x+4 are the numbers where x=odd integer
x+(x+2)+(x+4)=51
3x+6=51
3x=51-6
3x=45
x=45/3
x=15, x+2=17, x+4=19
also you can do the following...
51/3=17
17-2=15
and 17+2=19
3 0
3 years ago
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