I'm assuming you need to evaluate/simplify the equation, so you need to isolate/get x by itself in the equation:
2(3x + 1) = 11 Divide by 2 on both sides
3x + 1 =
[11/2 or 5.5] Subtract by 1 on both sides
[make the denominator the same to combine fractions]
3x =
Divide by 3 on both sides
x =
Answer:
It will take at least 15 weeks
Step-by-step explanation:
12w+31 ≥ 205
Subtract 31 from each side
12w+31-31 ≥ 205-31
12w ≥ 174
Divide each side by 12
12w/12 ≥ 174/12
w ≥ 14.5
Rounding up to the nearest integer
w ≥ 15
It will take at least 15 weeks
Answer:
false
Step-by-step explanation:
any line segment or distance has only one midpoint.
there is only one middle to everything.
how would that look like, if something had 2 middles ?
then they would not be a middle, and the middle between these 2 middles would then be the real middle ...
Answer:
A
Step-by-step explanation:
Hihi. So, this is a nice application of interest rates as well as properties of exponentials/logarithms. As you know, the basic equation for interest rates is A= Pe^(rt) where A is your final amount, P is your initial, r is your rate of interest, and t is the time the money was accumulating interest. After cleaning up, you get in a situation due to you having e still lying around. Luckily, if you take the natural log of e, all you have left behind is the previous exponent. Thus, you can take the natural log of both sides, divide by 4, and then simplify to see that your final interest rate is ~6%
Answer:
At least 202.44 mm in the top 15%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

How many yearly mm of rainfall would there be in the top 15%?
At least X mm.
X is the 100-15 = 85th percentile, which is X when Z has a pvalue of 0.85. So X when Z = 1.037.




At least 202.44 mm in the top 15%.