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elena-14-01-66 [18.8K]
3 years ago
13

What is 8.05 x 10/-5 in standard notation

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0

Answer:

0.0000805

Step-by-step explanation:

8.05×10⁻⁵ = 8.05×0.00001 = 0.0000805

ivann1987 [24]3 years ago
4 0

Answer:

The number given in standard notation is 0.0000805

Step-by-step explanation:

When you work with very large or very small numbers, you use scientific notation for numbers those quantities. Scientific notation is based on the idea that it is easier to read an exponent than to count many zeros in a number.

In scientific notation a number (between 1 and 10) is multiplied by a power (positive or negative) of base 10. The power to which the base is raised represents the number of times the comma moves. It is always an integer, positive if it moves to the left, or negative if the comma moves to the right.

To write this number in decimal notation, you convert the power of 10 into a series of zeros between the number and the decimal point. Since the exponent is negative, all those zeros go to the left of the number 8. For each power of 10, move the decimal point one place to the right. You should keep in mind that the number of zeros after the decimal point will always be 1 less than the exponent.

Taking into account everything previously said <u><em>the number given in standard notation is 0.0000805 </em></u>

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3 years ago
The first term of a geometric sequence is equal to a and the common ratio of the sequence is r.
ololo11 [35]

Answer: (a)  {a, ar, ar², ar³, ar⁴, ar⁵...}, (b)  arⁿ⁻¹

For part (a), the question gives us the first term a, and then asks us to apply the common ratio r six times.

In order for ar = a, the nth term of r will have to equal 0 (this implies that n is an exponent; thus giving us the first term a, as r = 1).

Since we use this method on the first term, we must use it for the next five, in which r gains an additional exponent for every consecutive value (nth term) thereafter.  

Ultimately getting: {a, ar, ar², ar³, ar⁴, ar⁵...}

For part (b), we first have to understand that the sequence does not start at 0, but at 1 for n. In order for ar = a, with n = 1, there needs to be subtraction of -1 within the exponent. So that arⁿ⁻¹

If we check and apply this, we can see that:

{ar¹⁻¹, ar²⁻¹, ar³⁻¹, ar⁴⁻¹, ar⁵⁻¹, ar⁶⁻¹...} = {a, ar, ar², ar³, ar⁴, ar⁵...} = arⁿ⁻¹ = Tn

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3 years ago
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I hoped this help! And have a •AMAZING• day :3

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2 years ago
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