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elena-14-01-66 [18.8K]
3 years ago
13

What is 8.05 x 10/-5 in standard notation

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0

Answer:

0.0000805

Step-by-step explanation:

8.05×10⁻⁵ = 8.05×0.00001 = 0.0000805

ivann1987 [24]3 years ago
4 0

Answer:

The number given in standard notation is 0.0000805

Step-by-step explanation:

When you work with very large or very small numbers, you use scientific notation for numbers those quantities. Scientific notation is based on the idea that it is easier to read an exponent than to count many zeros in a number.

In scientific notation a number (between 1 and 10) is multiplied by a power (positive or negative) of base 10. The power to which the base is raised represents the number of times the comma moves. It is always an integer, positive if it moves to the left, or negative if the comma moves to the right.

To write this number in decimal notation, you convert the power of 10 into a series of zeros between the number and the decimal point. Since the exponent is negative, all those zeros go to the left of the number 8. For each power of 10, move the decimal point one place to the right. You should keep in mind that the number of zeros after the decimal point will always be 1 less than the exponent.

Taking into account everything previously said <u><em>the number given in standard notation is 0.0000805 </em></u>

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The slope of EF¯¯¯¯¯ is −52.
9966 [12]

Based on the above, the segments that are perpendicular to EF are LM and NP.

<h3>Why is the segment are LM and NP perpendicular  to EF ?</h3>

Note that when two lines are perpendicular, we can say that;

M1 * M2 = -1 As M1 and M2 are known to be the slopes of the lines.

Therefore, when the the slope of EF is said to be −5/2, then  one can say that the slope of  the segment that is said to be  perpendicular to EF will have to be equal to m1*m2=-1, m2=-1/m1, m2=-1/(-5/2) or m2=2/5.

Scenario one:

JK , if J is at (3, −2) and K is at (5, −7)

To find the slope JK, then

m=(y2-y1)/x2-x1)

m=(-7+2)/(5-3)

m=-5/2

-5/2 is not equal to 2/5

Therefore,  JK is not perpendicular to EF

Scenario 2

Find GH , when G is at (6, 7) and H is at (4, 12)

To find the slope GH

m=(y2-y1)/x2-x1)

m=(12-7)/(4-6)

m=5/-2

m=-5/2

Since -5/2 is not equal to 2/5 then GH is not perpendicular to EF

Scenario 3:

Find LM , If L is at (1, 9) and M is at (6, 11)

To find the slope LM, then

m=(y2-y1)/x2-x1)

m=(11-9)/(6-1)

m=2/5

Since 2/5 is equal to 2/5

Then LM is perpendicular to EF

Scenario 4:

Find NP , if N is at (−3, 4) and P is at (−8, 2)

To find the slope NP, then

m=(y2-y1)/x2-x1)

m=(2-4)/(-8+3)

m=-2/-5

m=2/5

Since 2/5 is equal to 2/5.

Therefore,  NP is perpendicular to EF

Based on the above calculations, the segments that are perpendicular to EF are LM and NP.

See correct format of question written below

The slope of EF is −5/2 .

Which segments are perpendicular to EF?

Select all the right answers please

1. JK , where J is at (3, −2) and K is at (5, −7)

2. GH , where G is at (6, 7) and H is at (4, 12)

3. LM , where L is at (1, 9) and M is at (6, 11)

4. NP , where N is at (−3, 4) and P is at (−8, 2)

Learn more about segments from

brainly.com/question/10565562

#SPJ1

5 0
2 years ago
In Australia, road distance is measured in kilometres.
maks197457 [2]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Anastaziya [24]

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Linear algebra is a fundamental component of continuum mechanics (and most engineering disciplines). Solve the following matrix
Mars2501 [29]

Answer:

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C) The tensor product is attached below

D ) The value of X = F.X is attached below

Step-by-step explanation:

attached below is the detailed solution of the above problem

A) for the vectors ( u ) and ( v ) to be orthogonal to each other [ U.V has to be = 0 ] but in this scenario  U.V = 4 hence they are not orthogonal to each other

b) The vector normal to plane is gotten by : U x V

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