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elena-14-01-66 [18.8K]

3 years ago

13

What is 8.05 x 10/-5 in standard notation

2 answers:

Sladkaya [172]3 years ago

8 0

Answer:

0.0000805

Step-by-step explanation:

8.05×10⁻⁵ = 8.05×0.00001 = 0.0000805

ivann1987 [24]3 years ago

4 0

Answer:

The number given in standard notation is 0.0000805

Step-by-step explanation:

When you work with very large or very small numbers, you use scientific notation for numbers those quantities. Scientific notation is based on the idea that it is easier to read an exponent than to count many zeros in a number.

In scientific notation a number (between 1 and 10) is multiplied by a power (positive or negative) of base 10. The power to which the base is raised represents the number of times the comma moves. It is always an integer, positive if it moves to the left, or negative if the comma moves to the right.

To write this number in decimal notation, you convert the power of 10 into a series of zeros between the number and the decimal point. Since the exponent is negative, all those zeros go to the left of the number 8. For each power of 10, move the decimal point one place to the right. You should keep in mind that the number of zeros after the decimal point will always be 1 less than the exponent.

Taking into account everything previously said <u><em>the number given in standard notation is 0.0000805 </em></u>

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Y=-1/3x^2-4x-5 in vertex form

grigory [225]

Answer:

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

Step-by-step explanation:

Given function:

$Y=-\frac{1}{3}x^2-4x-5$

We need to find the vertex form which is.,

$y=a(x-h)^2+k$

where $(h,k)$ represents the co-ordinates of vertex.

We apply completing square method to do so.

We have

$Y=-\frac{1}{3}x^2-4x-5$

First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

$-3\times Y=-3\times\frac{1}{3}x^2-(-3)\times4x-(-3)\times 5$

$-3Y=x^2+12x+15$

Isolating $x^2$ and $x$ terms on one side.

Subtracting both sides by 15.

$-3Y-15=x^2+12x-15-15$

$-3Y-15=x^2+12x$

In order to make the right side a perfect square trinomial, we will take half of the co-efficient of $x$ term, square it and add it both sides side.

square of half of the co-efficient of $x$ term = $(\frac{1}{2}\times 12)^2=(6)^2=36$

Adding 36 to both sides.

$-3Y-15+36=x^2+12x+36$

$-3Y+21=x^2+12x+36$

Since $x^2+12x+36$ is a perfect square of $(x+6)$ , so, we can write as:

$-3Y+21=(x+6)^2$

Subtracting 21 to both sides:

$-3Y+21-21=(x+6)^2-21$

$-3Y=(x+6)^2-21$

Dividing both sides by -3.

$\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}$

$Y=-\frac{1}{3}(x+6)^2+7$ [Vertex form]

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Answer:

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