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2 years ago

Suppose f(x) = x2 and g(x)= (1/4x)2Which statement best compares the

Mathematics

1 answer:

kodGreya [7K]2 years ago

5 0

Answer:

Step-by-step explanation:

Since the variable <em>b</em> is manipulated in f(x) = a(bx - h)² + k, we are dealing with horizontal compression and stretching. Since b < 1, that means the graph is being horizontally compressed.

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Select the statements that are true based on the following given information. D = {x | x is a whole number} E = {x | x is a perf

likoan [24]

<h3>2 Answers: Choice C and Choice D</h3>

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Explanation:

Let's write the roster notation of each set

D = {0, 1, 2, 3, ...} the dots indicate the pattern goes on forever

E = {0, 1, 4, 9, 16, 25} = list of perfect squares smaller than 36

F = {20, 22, 24, 26, 28, 30} = even numbers between 20 and 30

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If we intersect sets D and E, we're looking for what numbers are in both sets at the same time. Therefore, D ∩ E = {0, 1, 4, 9, 16, 25} which is the exact same as set E. This is because all of set E is inside of set D. We say that set E is a subset of set D. So, D ∩ E = E.

Choice A is very close to being true. The problem is that 25 is missing from the set {1,4,9,16}. So this is why choice A is false.

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Now let's intersect sets D and F. The numbers they have in common are {20, 22, 24, 26, 28, 30} which is exactly what set F is. So set F is a subset of set D. We can write D ∩ F = F in much the same way we can say D ∩ E = E.

D ∩ F = {12,14,16,18} is not true. A number like 12 is not between 20 and 30, so it cannot be in set F.

Choice B is false so we cross it off the list.

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Choice C is true and here's why

D ∪ (E ∩ F) is the same as saying D ∪ G where G is the set of intersecting E and F together. In other words, G = E ∩ F

We don't really need to even worry about sets E, F or G. All that matters here is set D.

When we write D ∪ (E ∩ F) or D ∪ G, we're saying "a number is in set D, or it is in set G". If it is in D, then it's a whole number. Otherwise, it's in a subset of whole numbers.

Overall, D ∪ G and D ∪ (E ∩ F) form the entire set of whole numbers.

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Choice D is true.

E and F have nothing in common

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

So intersecting them leads to the empty set. This is the set with nothing inside it, not even 0.

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Choice F is false

These two sets below

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

union together to get

H = {0,1,4,9,16,20,22,24,25,26,28,30}

just toss all of the numbers together into one big set

Notice how each of these numbers are whole numbers, so they are part of set D. This means set H is also a subset of set D.

When we intersect sets D and H, we end up with set H. We do not simply end up with the set with 25 only inside it.

6 0

3 years ago

Terry Sheehan owns property assessed at $390,000 and pays a property tax rate of 1.69 per hundred dollars of assessed value. He

34kurt

Answer:

$1689

Step-by-step explanation:

Excess of rent amount over annual property tax bill = annual rent - annual property tax

annual property tax = [(assessed property value / 100) x 1.69]

( $390,000 / 100) x 1.69 = $6591

Annual rent = $690 x 12 = $8280

$8280 - $6591 = $1689

7 0

2 years ago

In a coordinate plane what is the difference between (-3 1/2, 4) and (2 1/2)?

Gala2k [10]

Answer:

Step-by-step explanation:

By difference I think you mean how far away from? I don't really know what you mean by this but I will try to help.

1/2-4=-3 1/2

2-(-3 1/2)=5 1/2

5 1/2

Above is a fraction.

I hope that I helped. Sorry if it wasn't the answer you were looking for.

4 0

2 years ago

sandy has $200 in her bank account. if she writes 6 checks for exactly $19.98, what expression describes the change in her bank

kkurt [141]

6x+19.98=200
200-19.98=6x
X= 200-19.98/6
= solve for it.

7 0

2 years ago

Read 2 more answers

How do I solve polynomials

spin [16.1K]

Answer:

Polynomial comes from poly- (meaning "many") and -nomial (in this case meaning "term") ... so it says "many terms"

Also they can have one or more terms, but not an infinite number of terms.

These are polynomials:

x − 2

−6y2 − ( 79)x

3xyz + 3xy2z − 0.1xz − 200y + 0.5

512v5 + 99w5

(Yes, "5" is a polynomial, one term is allowed, and it can be just a constant!)

These are not polynomials

3xy-2 is not, because the exponent is "-2" (exponents can only be 0,1,2,...)

2/(x+2) is not, because dividing by a variable is not allowed

1/x is not either

√x is not, because the exponent is "½" (see fractional exponents)

But these are allowed:

x/2 is allowed, because you can divide by a constant

also 3x/8 for the same reason

√2 is allowed, because it is a constant (= 1.4142...etc)

Monomial, Binomial, Trinomial

There are special names for polynomials with 1, 2 or 3 terms:

monomial, binomial, trinomial

Variables

Polynomials can have no variable at all

Example: 21 is a polynomial. It has just one term, which is a constant.

Or one variable

Example: x4 − 2x2 + x has three terms, but only one variable (x)

Or two or more variables

Example: xy4 − 5x2z has two terms, and three variables (x, y and z)

What is Special About Polynomials?

Because of the strict definition, polynomials are easy to work with.

For example we know that:

If you add polynomials you get a polynomial

If you multiply polynomials you get a polynomial

So you can do lots of additions and multiplications, and still have a polynomial as the result.

Also, polynomials of one variable are easy to graph, as they have smooth and continuous lines.

Example: x4−2x2+x

x^4-2x^2+x

See how nice and

smooth the curve is?

You can also divide polynomials (but the result may not be a polynomial).

Degree

The degree of a polynomial with only one variable is the largest exponent of that variable.

Example:

4x3-x-3 The Degree is 3 (the largest exponent of x)

For more complicated cases, read Degree (of an Expression).

Standard Form

The Standard Form for writing a polynomial is to put the terms with the highest degree first.

Example: Put this in Standard Form: 3x2 − 7 + 4x3 + x6

The highest degree is 6, so that goes first, then 3, 2 and then the constant last:

x6 + 4x3 + 3x2 − 7

You don't have to use Standard Form, but it helps.

5 0

2 years ago