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Deffense [45]
3 years ago
14

Suppose f(x) = x2 and g(x)= (1/4x)2Which statement best compares the

Mathematics
1 answer:
kodGreya [7K]3 years ago
5 0

Answer:

B.

Step-by-step explanation:

Since the variable <em>b</em> is manipulated in f(x) = a(bx - h)² + k, we are dealing with horizontal compression and stretching. Since b < 1, that means the graph is being horizontally compressed.

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The radius of a circle is 3 miles. What is the circle's diameter?
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Answer: 6 miles

Step-by-step explanation:

The diameter is 2x the radius

2 x 3 = 6

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Circle O is shown. Line segments E O and E O are radii with length 24. Angle D O E is 45 degrees. The area within sector D O E i
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How many solutions does the following equation have? ln(x2 + 4x − 5) = 0
lisov135 [29]
Alrighty
remember
log_a(b)=c means a^c=b
and
ln(x)=log_e(x)
and
x^0=1 for all real values of x
so

ln(x^2+4x-5)=0 means
log_e(x^2+4x-5)=0 means
e^0=x^2+4x-5 which simplifies to
1=x²+4x-5
minus 1 both sides
0=x²+4x-6
use quadratic formula or complete the square
x=-2+\sqrt{10} and x=-2-\sqrt{10}
2 solutions
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
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