All categories

3 years ago

32 + 7 + 2 22 + 192 + 24 + 8 22 + 3 + 2 − 22 − 7 − 15 ÷ 2 − 2

Mathematics

2 answers:

ycow [4]3 years ago

8 0

Answer:

1265.5

is that right

i think that question is wrong

mote1985 [20]3 years ago

4 0

Answer:

So simple question ask some complicated na yrr

You might be interested in

Anybody know the answer?

disa [49]

All triangles will add up to 180 degrees so subtract 58 from that and divide that by 2

4 0

3 years ago

A phone company has a monthly cellular plan where a customer pays a flat monthly fee and then a certain amount of money per minu

jok3333 [9.3K]

Answer:

Linear equation for the monthly cost of the cell plan is $10+0.15x$

Step-by-step explanation:

Let u denotes a flat monthly fee and v denotes amount charged per minute.

As the monthly cost is $71.50 if a customer uses 410 minutes,

$71.50=u+410v$ (i)

As the monthly cost is $118 if a customer uses 720 minutes,

$118=u+720v$ (ii)

Subtract (i) from (ii)

$118-71.50=u+720v-u-410v\\46.5=310v\\v=\frac{46.5}{310}\\ v=0.15$

Put $v=0.15$ in (i)

$71.50=u+410(0.15)\\71.50=u+61.5\\u=71.50-61.5\\u=10$

As x denotes the number of monthly minutes used,

linear equation for the monthly cost of the cell plan is $10+0.15x$

5 0

3 years ago

I am lost on "Graph y< -3|x-1| please help!

Sindrei [870]

1) |x| is the absolute value function. Its vertex is at (0,0).

2) |x-1| has the same graph as does y = |x|, except that the vertex is shifted 1 unit to the left.

3) -3|x-1| has the same graph as the previous result, except that we must reflect the previous graph in the x-axis.

4) Replace the solid lines you used in this graph with dashed ones.

5) Shade the area beneath y = -3|x-1|

In summary:

the desired graph is the shaded area below the inverted v-shaped graph of

y = -3|x-1|. Its vertex is at (-1,0).

6 0

4 years ago

What is the root square of 10,000,000

cupoosta [38]

5,000,000 because that is half of 10,000,000

8 0

3 years ago

Read 2 more answers

If f(x)=3x+2 and g(x)=x^2-3x-4, what is (g0f)(5)

andre [41]

$\bf \begin{cases} f(x)=3x+2\\ g(x)=x^2-3x-4\\[-0.5em] \hrulefill\\ (g\circ f)(5)=g(~~f(5)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(5)=3(5)+2\implies f(5)=17 \\\\[-0.35em] ~\dotfill\\\\ g(~~f(5)~~)\implies g(~~17~~)=(17)^2-3(17)-4\implies g(17)=289-58-4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{(g\circ f)(5)}{g(17)=227}~\hfill$

8 0

3 years ago