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brilliants [131]
4 years ago
7

NEED HELP NOW

Mathematics
1 answer:
umka2103 [35]4 years ago
7 0
The area of a trapezoid is the height times the average of the two bases, mathematically:

A=h(b1+b2)/2, in this case h=6in, b1=9in, and b2=7in so

A=6(9+7)/2

A=6*16/2

A=48in^2
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The difference of 7 and a number x is 10
Dovator [93]

that is 7X=10

= 1.42857143 or about1.42

5 0
4 years ago
What is the distance between Point K and Point L?
lutik1710 [3]

Answer:

( 7, 2 )

Step-by-step explanation:

I hope this helps you!

3 0
3 years ago
Each of forty-one pet owners was asked, "Does your pet eat more dry food or wet food?" Here are the results. Among the cat owner
Amiraneli [1.4K]

Answer: No, pet does not eat more dry food than wet food.

Step-by-step explanation:

Since we have given that

In case of cat owner,

Number who chose Dry food = 6

Number who chose Wet food = 8

In case of dog owners,

Number who chose Dry food = 14

Number who wet food = 13

So,Total number who chose Dry food = 6+14=20

Total number who chose Wet food = 8+13=21

So, the answer for this question ""Does your pet eat more dry food or wet food?" is No.

Hence, No, pet does not eat more dry food than wet food.

4 0
3 years ago
In ΔABC, AC = BC, CD ⊥ AB with D ∈ AB , AB = 4 in, and CD = sqrt3 in. Find AC.
amid [387]
Check the picture below.

segments AC and BC are equal, that means that ABC is an isosceles triangle, with twin sides.  Now the twin sides make twin angles on the opposite side, namely the angles at A and B are twins.

if the angles at A and B are twins, and CD is ⟂ to AB, there's only one possibility that can happen, and is if CD is an angle bisector at C.

an angle bisector like CD with twin angles on each side, will cut AB in two equal halves, therefore, if AB = 4, then AD = 2 and DB = 2.

8 0
3 years ago
The path of a projectile launched from a 16-ft-tall tower is modeled by the equation y = −16t2 + 64t +16. What is the maximum he
Aleks04 [339]

Answer:

<h3>80 feet</h3>

Step-by-step explanation:

Given the path of a projectile launched from a 16-ft-tall tower modeled by the equation y = −16t^2 + 64t +16

h is the maximum height reached

t is in seconds

The velocity of the projectile at its maximum height is zero;

velocity v = dy/dt

v = -32t + 64

Since v = 0 at maximum height

0 = -32t + 64

32t = 64

t = 2secs

Substitute t = 2secs into the equation of the height to get the maximum height.

y = −16t^2 + 64t +16

at t = 2secs

y = −16(2)^2 + 64(2) +16

y = -64 + 128 + 16

y = 64+16

y = 80 feet

Hence the maximum height, in feet, reached by the projectile is 80 feet

5 0
3 years ago
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