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FrozenT [24]
4 years ago
12

Dianna and Becky were playing on the same soccer team and took turns being goalie. They stoped 9 out of 10 shots made against th

em. If the other team scored 3 points, how many balls did Dianna and Becky stop from going into the net?
Mathematics
1 answer:
vitfil [10]4 years ago
6 0

Answer:

27 balls

Step-by-step explanation:

If Dianna and Becky stopped 9 out of 10 shots made against them.

It means they allowed in 1 out of 10 shots made against them.

This is best solved using ratios

Proportion of Shots Stopped : Proportion of Shots allowed=9:1

If the other team scores 3 points, it means the number of shots allowed =3

Let x be the number of shots stopped

Number of Shots Stopped : Number of Shots allowed=x:3

Therefore:

9:1=x:3

\frac{9}{1}=\frac{x}{3}

Cross multiplying

x=9 X 3 =27

Dianna and Becky stopped 27 balls from going into the net,

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b. (29673.9301 , 32008.0699)

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on calculation, we find that sample mean = 30843 and sample standard deviation = 3018.504, and n=20

1)

Sample Mean = 30841

SD = 3000

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 670.8204

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Margin of Error (ME) = z(a/2) x SE = 1314.808

95% confidence interval is given by:

Sample Mean +/- (Margin of Error) = 30841 +/- 1314.808

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2)when std dev of population is not known, we use sample's, but we have to use t instead of z

Sample Mean = 30841

SD = 3018.504

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 674.958

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we use t-distribution as population standard deviation is unknown

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Margin of Error (ME) = t(a/2,n-1)x SE = 1167.0699

90% confidence interval is given by:

Sample Mean +/- (Margin of Error)

30841 +/- 1167.0699 = (29673.9301 , 32008.0699)

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