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3 years ago

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a sayian's power level is 400 septillion if he goes super sayian 3 and it multiplies his power by 900 trillion what is his power

level in super sayian 3

2 answers:

QveST [7]3 years ago

7 0

It's over 9 thousand

Akimi4 [234]3 years ago

7 0

Answer:

3.6e+41 the e+ means the amount of 0s i think so

3,600,000,000,000,000,000,000,000,000,000,000,000,000,000

but for the record the super saiyan 3 transformation is supposed to be a 400x multiplier so his actual power level would be 3.6e+29 or 3,600,000,000,000,000,000,000,000,000,000

Step-by-step explanation:

im a db fan and i own a calculator

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How to multiply numbers with exponets and different bases

o-na [289]

When the bases are diffenrent and the exponents of a and b are the same, we can multiply a and b first:
a n ⋅ b n = (a ⋅ b) n
Example:
32 ⋅ 42 = (3⋅4)2 = 122 = 12⋅12 = 144

When the bases and the exponents are different we have to calculate each exponent and then multiply:
a n ⋅ b m
Example:
32 ⋅ 43 = 9 ⋅ 64 = 576

5 0

3 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

8 0

2 years ago

Can you construct a triangle that has side lengths 2 yd, 9 yd, and 10 yd?

yan [13]

Yes

The rule to check if a triplet of numbers can represent the sides of a triangle is the following: the sum of the length of two sides must exceed the third one.

This happens for all possible couples in your case:

$2+9=11>10$

$2+10=12>9$

$9+10=19>2$

3 0

2 years ago

What is ratio of 28 red pens and 84 black pens

Setler [38]

Ratio

28:84

If you want it simplified
it would be
1:3<span />

8 0

3 years ago

Read 2 more answers

2 2/4 devided by 1/6

lara31 [8.8K]

(15 is your answer)

Divide numerator by denominator, cancel out any common factors

5 0

3 years ago