Hi!
So basically, you can set this up in a proportion.
For every gallon of punch, 2 cups of cranberry juice is needed. What you need to find is the amount of cranberry juice is needed for one gallon. So then you would have to set up your proportion like this:
![\frac{2}{3} = \frac{x}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20%3D%20%20%5Cfrac%7Bx%7D%7B1%7D%20)
then you would have to cross multiply, and you should have something like this:
3x = 2
then using division you should have this:
x =
![\frac{2}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20)
so you would need 2/3 cups of cranberry juice for one gallon of punch. :)
hopefully this makes sense, lol.
When a car ends up 0 m from its starting point.....this means that the distance driven is the same distance when coming back
The car first travels a distance of 9 meters, and then travels 9 meters in the opposite direction <=== 9 - 9 = 0
Answer:
BC
Step-by-step explanation:
the height of a right-angled triangle to the Hypotenuse is the square root of the product of the lengths of the 2 segments of the Hypotenuse.
so the square of the height is then the product of the 2 line segments of the Hypotenuse.
therefore
AC² = DC × BC
Answer:
The height of the ball is less than 17 feet for t > 2 seconds.
Step-by-step explanation:
The height of the ball after t seconds is given by the following equation:
![h(t) = -16t^{2} + 81](https://tex.z-dn.net/?f=h%28t%29%20%3D%20-16t%5E%7B2%7D%20%2B%2081)
For which interval of the time is the height of the ball less than 17 feet
This is t for which:
![h(t) < 17](https://tex.z-dn.net/?f=h%28t%29%20%3C%2017)
So
![-16t^{2} + 81 < 17](https://tex.z-dn.net/?f=-16t%5E%7B2%7D%20%2B%2081%20%3C%2017)
![16t^{2} < -64](https://tex.z-dn.net/?f=16t%5E%7B2%7D%20%3C%20-64)
Multiplying by -1
![16t^{2} > 64](https://tex.z-dn.net/?f=16t%5E%7B2%7D%20%3E%2064)
![t^{2} > \frac{64}{16}](https://tex.z-dn.net/?f=t%5E%7B2%7D%20%3E%20%5Cfrac%7B64%7D%7B16%7D)
![t^{2} > 4](https://tex.z-dn.net/?f=t%5E%7B2%7D%20%3E%204)
![t > \sqrt{4}](https://tex.z-dn.net/?f=t%20%3E%20%5Csqrt%7B4%7D)
![t > 2](https://tex.z-dn.net/?f=t%20%3E%202)
The height of the ball is less than 17 feet for t > 2 seconds.