If the line is parallel, then the second equation has the same slope. The slope of the first line is -7, so the initial equation is going to be y=-7x+b. Plug in the points given, so you get -8=-7(7)+b. You have to solve for b, so move the equation around. b=41. The equation is y=-7x+41

8 0

4 years ago

I need help to solve this proportion

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

cross multiply

isolate x

12x=7.5(8)

12x=60

12x/12=60/12

5 is the answer

5 0

3 years ago

Find the oth term of the geometric sequence 7, 14, 28, ...

yaroslaw [1]

Answer:

The nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

Step-by-step explanation:

Given the geometric sequence

7, 14, 28, ...

We know that a geometric sequence has a constant ratio 'r' and is defined by

$a_n=a_1\cdot r^{n-1}$

where a₁ is the first term and r is the common ratio

Computing the ratios of all the adjacent terms

$\frac{14}{7}=2,\:\quad \frac{28}{14}=2$

The ratio of all the adjacent terms is the same and equal to

$r=2$

now substituting r = 2 and a₁ = 7 in the nth term

$a_n=a_1\cdot r^{n-1}$

$a_n=7\cdot \:2^{n-1}$

Therefore, the nth term of the geometric sequence 7, 14, 28, ... is:

$a_n=7\cdot \:2^{n-1}$

6 0

3 years ago