Question

An automobile engineer is redesigning a conical chamber that was originally specified to be 12 inches long with a circular base of diameter 5.7 inches. In the new design, the chamber is scaled by a factor of 1.5. The volume of the original chamber is a.)102.02 b.)248.04 c.)306.06 d.)412.08 cubic inches. This is a.)242.47 b.)344.49 c.)432.16 d.)448.21 cubic inches less than the volume of the new chamber.

Answer 1

The problem asked us to solve the volume of a cone. Given that the height is h=12 and has a base of D=5.7 inches in diameter. To solve this we use the equation:
V=pi(D/2)^2(h/3) substitutiing, the answer is 102.07in^3
After scaling up the answer is 344.49in^3. This answer was derived by multiplying each dimension with the scaling factor of 1.5 then using the equation above to solve the volume.