Which of the following is an extraneous solution of startroot 4 x 41 endroot = x 5? x = –8 x = –2 x = 2 x = 8
2 answers:
Answer:
its not d! its a -8
Step-by-step explanation:
The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.
<h3>What is an extraneous solution?</h3>
It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation .
✓4x + 41 = x + 5
Square both sides
4x + 41 = x² + 10x + 25
x² + 6x - 16
x(x + 8) - 2(x + 8) = 0
x + 8 = 0
x= 0 + 8 = 8
Learn more about extraneous solution on:
brainly.com/question/295656
#SPJ4
You might be interested in
You have the length of the sides? If not: a and b is the length of the scratch, h is the height <span>This lateral surface area = 2ah+2bh=2h(a+b)</span>
The answer is A my friend.
Answer:
5:8
Step-by-step explanation:
Answer:
1 2 0 c a n s
Step-by-step explanation:
1 carton = 24 cans
therefore, 5 * 24 = 1 2 0
