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3 years ago

What is 100 divided by -60

Mathematics

2 answers:

Marianna [84]3 years ago

7 0

Answer:

-1.67

Step-by-step explanation:

100÷-60 how many times does -60 go into a 100

egoroff_w [7]3 years ago

6 0

Answer:-5/3

Step-by-step explanation:

First we write as a fraction : 100/-60

Simplifying: 10/-6

= 5/-3

=-5/3

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What is the slope of 6x-3y=18??

dolphi86 [110]

$the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\6x-3y=18 \\ \\-3y=-6x+18 \ \ /:(-3)\\ \\y=\frac{-6}{-3}x + \frac{18}{-3} \\ \\y=2x-6 \\ \\ m = 2$

6 0

2 years ago

Prove that 25^11−5^19 is divisible by 31.

SCORPION-xisa [38]

Answer:

Divisible by 3 is the answer

Step-by-step explanation:

First get everything to have the same base of 5

25^11 - 5^19

(5^2)^11 - 5^19

5^(2*11) - 5^19

5^22 - 5^19

Now factor out the GCF 5^19 to get

5^22 - 5^19

5^(19+3) - 5^(19+0)

5^19*5^3 - 5^19*5^0

5^19(5^3 - 5^0)

5^19(125 - 1)

5^19*(124)

At this point, we factor the 124 into 31*4 to end up with this full factorization: 5^19*31*4

Therefore, 25^11 - 5^19 is equivalent to 5^19*31*4

Since 31 is a factor of the original expression, this means the original expression is divisible by 31.

4 0

3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

Please help.........

Romashka-Z-Leto [24]

What you need help with

8 0

2 years ago

3[x]+9 what is the graph?

ipn [44]

So, you can do this one of two ways.

The first is knowing what the numbers in your equation represent:

For example: y=mx+b in this case "b" is 9. b is the y-value when x=0. So the first point on our graph is (0,9). Next we have to pick an xvalue to solve for another y-coordinate.

I chose x= -3. Plug x into the equation to get y.
y=3x+9
y=3(-3)+9
y=(-9)+9
y=0

So, our second point is (-3,0).

connect the points with a ruler to graph the line.

4 0

2 years ago