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LekaFEV [45]
3 years ago
5

The area A, of a rectangle is 120x (exponent of 2)+78x-90 , and a length, l, of the rectangle is 12x=15. which of the following

given width, W, of the rectangle?
A. 9x+4
B. 10x - 19
C. 10x-6
D. 8x -6
Mathematics
1 answer:
Akimi4 [234]3 years ago
6 0
I think answer should be c. Please give me brainlest I hope this helps let me know if it’s correct or not okay thanks bye
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3.<br>June has 248 oranges. She sells of these oranges. How many oranges did June sell?<br>Answer.​
uranmaximum [27]

Answer:

93. Divide 248 by 8. One eighth of 248 = 31.

June sold 3/8 of the 248 oranges.

If 1/8 = 31 and June sold 3/8 of the oranges.

Multiply 3 × 31. Therefore June sold 93 oranges.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
I need help please! asap
mihalych1998 [28]

Answer:

my guess is c

Step-by-step explanation:

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8 0
2 years ago
What is the best estimate of the sum of the fraction? 31/4 +17/3 +8/18
Bogdan [553]

The best estimate of the sum of the expression given is \rm 13 \dfrac {31}{26}

What is a Fraction ?

A fraction is written as p/q , where q \rm \ne 0

It is asked to determine the sum of the fraction

31/4 + 17/3 + 8/18

Taking the LCM of 4 , 3 , 18

LCM of 4 , 3 ,18 is 36

Therefore

\rm \dfrac{ 31 *9 + 17 *12 + 8 *2}{36 }

(279+204+16) /36

499 / 36

\rm 13 \dfrac {31}{26}

Therefore the best estimate of the sum of the expression given is \rm 13 \dfrac {31}{26}.

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brainly.com/question/10354322

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3 0
2 years ago
Americans receive an average of 20 Christmas cards each year. Suppose the number of Christmas cards is normally distributed with
soldier1979 [14.2K]

The distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

<h3>Probability</h3>

a. Distribution

X ~ N (20 , 6)

b. P(x ≤24)

= P[(x - μ ) / σ  (24 - 20) / 6]

= P(z  ≤0.67)

=  0.74857

=0.7486

Hence:

Probability = 0.7486

c. P(21 < x < 26)

= P[(21 - 26)/ 6) < (x - μ  ) / σ   < (24 - 20) / 6) ]

= P(-0.83 < z < 0.67)

= P(z < 0.67) - P(z < -0.)

=  0.74857- 0.2033

= 0.54527

Hence:

Probability =0.54527

d. Using standard normal table ,

P(Z < z) = 66%

P(Z < 0.50) = 0.66

z = 0.50

Using z-score formula,

x = z×  σ +  μ

x = 0.50 × 6 + 20 = 23

23 Christmas cards

Therefore the distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.

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8 0
2 years ago
Sue a tollbooth worker is paid $12.50 per hour between 8 Am and 4 pm. After 4 pm she is paid $14.25 per hour. If Sue works from
katrin2010 [14]

Answer:

She earns that day $103.5

Step-by-step explanation:

Lets explain how to solve the question

- She is paid $12.50 per hour between 8 am and 4 pm

- After 4 pm she is paid $14.25 per hour

- She works one particular day from 10 am to 6 pm

* Lets distribute her time of work into two part according to her

 payment above

# 1st part from 10 am to 4 pm

∵ She is paid $12.50 per hour between 8 am to 4 pm

∵ She works from 10 am to 4 pm

- Calculate how many hours between 10 am and 4 pm

∵ am and pm not like terms in time, so change the time to 24-hours

∵ 4 pm in 24-hour time is 4 + 12 = 16

∴ She works form 10 to 16

∴ She works for 6 hours (16  - 10 = 6)

∴ She is paid = 12.50 × 6 = $75

# 2nd part after 4 pm to 6 pm

∵ She is paid $14.25 per hour after 4 pm

∵ She works from 4 pm to 6 pm

- Calculate how many hours between 4 pm and 6 pm

∵ Both times are pm

∴ She works for 2 hours (6 - 4 = 2)

∴ She is paid = 14.25 × 2 = $28.5

- Add the two answers of the 1st part and the 2nd part

∴ She earns = 75 + 28.5 = $103.5

* She earns that day $103.5

7 0
3 years ago
Read 2 more answers
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