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julsineya [31]
4 years ago
5

Find a value for k such that the following trinomial can be factored x^2-8x+k

Mathematics
1 answer:
mr_godi [17]4 years ago
6 0

Answer:

16

Step-by-step explanation:

x^2-8x+k is a quadratic expression of the form ax^2 + bx + c.  Here a = 1, b = -8 and c = k.  Focus on x^2-8x and complete the square as follows:  Take half of the coefficient of x (that is, take half of -8) and square the result:

(-4)^2 = 16; if we now write x^2-8x+ 16, we'll have the square of (x - 4):  (x -4)^2.

Thus, k = 16 turns x^2-8x+k into a perfect square.

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Answer:

Quantity remaining= 27.5 grams

Step-by-step explanation:

If the initial quantity of the radioactive isotope= 220 grams

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Now for the second half life , the quantity to work with will be 110 grams

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For the third half life , the quantity to work with is 55 grams

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So after 3 half life's of this radioactive isotope, the amount remaining out of 220 = 27.5 grams.

Another simple way to do this

Since half life reduce the isotope by half of its original.

The third half life will reduce it by (1/2)^3= 1/8

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