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bija089 [108]
2 years ago
7

Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply​

Mathematics
1 answer:
kykrilka [37]2 years ago
6 0

\cos(2x)  =  \cos(x)

Solution (1)

2x = x + 2k\pi

2x - x = 2k\pi

x = 2k\pi

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

2x =  - x  + 2k\pi

2x + x = 2k\pi

3x = 2k\pi

x =  \frac{2k\pi}{3}

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

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