Solution (1)
for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)
x=0 / x=2π/3 / x=-2π/3
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
Answer:
13
Step-by-step explanation:
7 6/7
× =
=
optionb
<u>Step-by-step explanation:</u>
Convert everything to "sin" and "cos" and then cancel out the common factors.