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bija089 [108]
3 years ago
7

Over the interval [0,2pi), what are the solutions to cos(2x) = cos(x)? check all that apply​

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0

\cos(2x)  =  \cos(x)

Solution (1)

2x = x + 2k\pi

2x - x = 2k\pi

x = 2k\pi

for k=0 / for k=1 / for k=-1

x=0 / x=2π / x=-2π

acc / acc / rej

solution (2)

2x =  - x  + 2k\pi

2x + x = 2k\pi

3x = 2k\pi

x =  \frac{2k\pi}{3}

for k=0 / for k=1 / for k=-1

x=0 / x=2π/3 / x=-2π/3

acc / acc / rej

Note that i'm trying values of K which make the answer belong to our interval;

So our solution which i will represent as a set is;

S € {0,2π/3,2π}

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Pls can someone help me with math pls I’m this is my last points..
LiRa [457]

Answer:

Please read all of this! Underlined things are the answers. The area of the entire circle is 19.625

Step-by-step explanation:

(This is a circle so the middle line is the diameter. According to the attachment, the diameter is 5 cm. To find the area, we have to multiply π and the radius squared. The radius is half of the diameter.

5 ÷ 2 = 2.5

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Ignore the top I just realized what I'm supposed to do but I left it there just in case you need help!

<u>The right and left shaded regions areas are 6.28 each.</u>

4 ÷ 2 = 2

2² = 4

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Since this is a semi circle, we cut it in half.

12.56 ÷ 2 = 6.28

To find the top and bottom shaded region's areas, repeat the same steps.

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1.5² = 2.25

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<u>The areas of the the top and bottom shaded regions are 3.5325 each.</u>

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