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ankoles [38]
2 years ago
11

Suppose a ball is thrown upward to a height of h0 meters. Each time the ballâ bounces, it rebounds to a fraction r of its previo

us height. Let hn be the height after the nth bounce and let Sn be the total distance the ball has traveled at the moment of the nth bounce. Complete parts a. and b below. h0 = 9, r = o.4Find the first four terms of the sequence (Se).
Mathematics
1 answer:
asambeis [7]2 years ago
6 0

Answer:What if you were asking this question? How would you explain it to yourself?

Step-by-step explanation:

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Marty drinks 2 cups of water each day. Katie drinks 14 times as much as Marty. How many fluid ounces of water do they drink all
Katena32 [7]
224 ounces.?
Gajhfiambzoandhiam
6 0
2 years ago
10.045+2.673+105.95 to the nearest whole number and then estimate the sum
horsena [70]

Answer:

119

Step-by-step explanation:

The nearest whole numbers from those listed are

10

3

106

The estimated sum = 119

The actual sum is 118.668

When you are doing a test, being able to estimate is a very powerful skill. 119 is close enough to the actual answer that you know your actual answer is likely correct.

5 0
3 years ago
What does this mean?<br> ~p~9
Montano1993 [528]
~p~9 .............
Show work
9=p
6 0
3 years ago
Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.
gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant  is  mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is  mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)

The partial derivatives of a function are f x and f y.

\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\

&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}

In conclusion,  the area is

A=3 √4 units ^2

Read more about the plane

brainly.com/question/1962726

#SPJ4

5 0
1 year ago
The scores on a 100 point exam are normally distributed with a mean of 80 and a standard deviation of 6. A student's score place
KonstantinChe [14]

Answer:

85-89

Step-by-step explanation:

7 0
2 years ago
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