If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
Answer:
Personification is your answer.
Hope it helps!!!
The answer is definitely B
Answer:
(2,4).
Step-by-step explanation:
Graph of y = f(-x).
The values of x in f(-x) assume the values of -x in f(x).
For example, f(-2) in f(x) is f(2) in f(-x), and f(2) in f(x) is f(-2) in f(-x).
b) Write down the coordinates of the maximum point of the graph of y = f(-x).
In f(x), we have that x = -2. So in f(-x), it will be x = 2. y remains unchanged. So
(2,4).
