The given expression is

And since we have x+2 common in numerator and denominator, there is a hole at x+2=0, that is at x=-2
And a function is undefined when denominator is zero. And at x=-6, denominator become zero.
So, at x=-6, the function is undefined, or there is a vertical asymptote at x=-6 and hole at x=-2 .
Answer is -5.
Explanation- Since t equals 0. You put 0 in place of every t.
0(2)- 2(0)- 5 =
0-0-5= -5
<span>2y-x=11</span>
<span>-x=11-2y
</span><span>x=-11+2y
</span><span><span>x=2y-11</span><span>
</span></span>
Answer:
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