All categories

3 years ago

3 more than the product of 2 and a number x

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

5 0

2x+3. that is the answer because 2 and a number is 2x and 3 more than that would be adding 3

You might be interested in

Help me on #8 on a-d please

Svet_ta [14]

A.) -13
b.) 17
c.) 80
d.) 1
All your doing is substituting x for the number in the parenthesis and matching it with the correct function. For example, f(-3) would be 2(-3)-7 which is equal to -6-7 which is -13.

6 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

3 years ago

Hello, I need help with this math problem please

Marina86 [1]

Answer:

4c^2+7c-5=0

4c^2+7c=5

4c^2+7c-5=0\quad :\quad c=\frac{-7+\sqrt{129}}{8},\:c=\frac{-7-\sqrt{129}}{8}\quad \left(\mathrm{Decimal}:\quad c=0.54472\dots ,\:c=-2.29472\dots \right)

Hope This Helps!!!

4 0

2 years ago

Read 2 more answers

Viktoria knows that it is impossible to remove a red marble from her bag that has no red marbles in it. If she reaches into the

Lesechka [4]

0 since theres no red marbles....?

7 0

3 years ago

Read 2 more answers

Element X is a radioactive isotope such that every 90 years, its mass decreases by half. Given that the initial mass of a sample

steposvetlana [31]

Answer:

approximately 27 grams

Work Shown:

Half life formula

y = A*(0.5)^(x/H)

where,

A = starting amount = 30 grams

H = half life period = 90 years

x = number of years that pass by = 12

y = amount left over after x years

Let's plug the values for x, A and H into the formula to find y

y = A*(0.5)^(x/H)

y = 30*(0.5)^(12/90)

y = 27.3516746567466

y = 27 .... rounding to the nearest whole number

4 0

3 years ago