Answer: 2/3
Step-by-step explanation:
First, find the probability of rolling an odd number. The odd numbers on a 6-sided die are 1, 3, and 5. This is a probability of 3/6.
Now, find the probability of rolling a 2. There's only one 2 on a die, so the probability is 1/6.
Next, add these together. 3/6 + 1/6 = 4/6. This can be reduced by dividing both the numerator and denominator by 2. This results in a final probability of 2/3.
Answer:
| 4x - 6 | = - 6
Step-by-step explanation:
The absolute value function always produces a positive value.
| 4x - 6 | = - 6 ← negative value is not possible
Answer:
(c) H0 should be rejected
Step-by-step explanation:
Null hypothesis (H0): population mean is equal to 5
Alternate hypothesis (Ha): population mean is greater than 5
Z = (sample mean - population mean) ÷ (sd/√n)
sample mean = 5.3, population mean = 5, sd = 1, n = 500
Z = (5.3 - 5) ÷ (1/√500) = 0.3 ÷ 0.045 = 6.67
Using the normal distribution table, for a one tailed test at 0.01 significance level, the critical value is 2.326
Conclusion:
Since 6.67 is greater than 2.326, reject the null hypothesis (H0)
Answer:
C
Step-by-step explanation:
Given
![\left[\begin{array}{ccc}-2&3\\2&4\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%263%5C%5C2%264%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}3&1\\-1&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%261%5C%5C-1%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Add corresponding elements to obtain the sum, that is
= ![\left[\begin{array}{ccc}-2+3&3+1\\2-1&4+2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%2B3%263%2B1%5C%5C2-1%264%2B2%5C%5C%5Cend%7Barray%7D%5Cright%5D)
= ![\left[\begin{array}{ccc}1&4\\1&6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C1%266%5C%5C%5Cend%7Barray%7D%5Cright%5D)
→ C
