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STALIN [3.7K]
3 years ago
11

Any number in the form of a+-bi, where a and b are real numbers and b is not equal to 0 is considered a pure imaginary number

Mathematics
2 answers:
lilavasa [31]3 years ago
7 0
Wrong those are considered complex numbers. pure imaginary numbers have ,0 for a and are thus in the form. 3i, -2i, 17i. etc
NISA [10]3 years ago
4 0

Answer:

<h2>False.</h2>

Step-by-step explanation:

<em>A pure imaginary number is a complex number that doesn't have a real part.</em>

So, if a is a real number, and it doesn't specify that a is only equal to zero, then the expression a+bi is not a pure imaginary number, it's only a complex number. Examples of imaginary numbers are 2i;3i;4i;....bi where b\inR

In this case, a\in R, that is, <em>a </em>can be 0, \±1, \±2, \±3, ...

<em>Therefore the statement is </em><em>false</em><em>, because a can take any real value.</em>

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