Any number in the form of a+-bi, where a and b are real numbers and b is not equal to 0 is considered a pure imaginary number
2 answers:
Answer:
<h2>False.</h2>Step-by-step explanation:
<em>A pure imaginary number is a complex number that doesn't have a real part.</em>
So, if a is a real number, and it doesn't specify that a is only equal to zero, then the expression a+bi is not a pure imaginary number, it's only a complex number. Examples of imaginary numbers are where
In this case, , that is, <em>a </em>can be
<em>Therefore the statement is </em><em>false</em><em>, because a can take any real value.</em>
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Answer:
f⁻¹(x) = + 7
Step-by-step explanation:
The inverse of a function reverses the operations performed by the function in the question such if f(x) = y, then we have, f⁻¹(y) = x, which reverses the operation of the first function.
The inverse of a function f(x) = 4·㏒₂(x - 7) is found as follows;
We have;
y = 4·㏒₂(x - 7)
We substitute x for y to get;
x = 4·㏒₂(y - 7) which gives;
x/4 = ㏒₂(y - 7)
= y - 7
y = + 7
Therefore;
f⁻¹(x) = + 7.