Any number in the form of a+-bi, where a and b are real numbers and b is not equal to 0 is considered a pure imaginary number
2 answers:
Answer:
<h2>False.</h2>Step-by-step explanation:
<em>A pure imaginary number is a complex number that doesn't have a real part.</em>
So, if a is a real number, and it doesn't specify that a is only equal to zero, then the expression a+bi is not a pure imaginary number, it's only a complex number. Examples of imaginary numbers are where
In this case, , that is, <em>a </em>can be
<em>Therefore the statement is </em><em>false</em><em>, because a can take any real value.</em>
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Answer:
Option D
Step-by-step explanation:
We have to find the value of the composite function (h o k)(2).
Since, (h o k)(x) = h[k(x)]
(h o k)(2) = h[k(2)]
From the picture attached,
At x = 2
k(2) = (-2)
Therefore, h[k(2)] = h(-2)
Since, h(x) =
Therefore, h(-2) =
= -3
(h o k)(2) = -3 is the answer.
Option (D) is the correct option.