Answer:
The slope of line MN is two thirds,
The slope of line RS is negative three-halves
and line RS is perpendicular to both line MN and PQ
Step-by-step explanation:
For the first two, I found the slope using the slope formula, and I know the third one is correct because that is what it says in the very beginning.
Hope this helped, sorry if it is a little hard to understand, it was pretty hard to understand. :)
The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Answer:
Literally take your f(x) and - your g(x)
(x^2+9x+18) - (x + 6)
Remember to distribute the negative sign.
Use gradient formula, rise over run.
y2-y1/x2-x1
The width would be x-4 and
Length would be x
Add all of the sides together
(x-4)+(x-4) + x + x =72,
Which would come out
4x-8=72
Subtract 8 fro, 72 and you get 64
Then divided 64 by 4
So. Width is 16 and length is 20 . given (x-4)
