Answer:
For the exponential distribution:


We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.



Step-by-step explanation:
The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".
For this case we have a large sample size n =60 >30
The exponential distribution is the probability distribution that describes the time between events in a Poisson process.
For the exponential distribution:


We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.



Answer:
go to the left 3.5 units then go down one and that's your point
Answer:
Capital: 2 400
Tasa: 5% = 5/100 = 1/20
Tiempo: 4 años
A) Interés = capital*tasa*tiempo
Interés = 2400*(1/20)*4
Interés = 480 soles
B) Interés = Capital*((1 + tasa)^tiempo+1)
Interés = 2400*((1 + 1/20)^4 + 1)
Interés = 2400*((21/20)^4 + 1)
Interés = 2400*(194 481/160 000 + 1)
Interés = 2400*(354 481/160 000)
Interés = 5 317,215Step-by-step explanation:
The answer should be A.
When we see the equation y=a^x we can relate to all the exponential functions, however, when the problem asked what points does all equations in that form pass through. I was instantly reminded by two facts.
One is that any number to the first is equal to itself. In other words, a^1=a
Another is that any number to the zero is equal to 1. a^x=1
if that is true, 1 will always be the x value since y=a^x and 0 will always be the x value because that is how y can be equal to one.
therefore, the answer is A: (0,1)