-0.5, 1 1/4, 0.25, 3/8 greatest to least decimal form

How can you tell the difference between an exponential equation, and linear equation by first glance?

Evgen [1.6K]

Answer:

An exponential equation will have a term that is squared (the tiny two that is after a number) and a linear equation will not.

8 0

3 years ago

At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca

saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

$p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064$

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that $P(A) = 0.3064$

Probability of testing positive while never using the drug.

11% of 75%. So

$P(A \cap B) = 0.11*0.75 = 0.0825$

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693$

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0

3 years ago

Ab is 10. 8 units long if ABC is dilated by a scale factor of k equals 1.3 what is the length of a'b'

Marizza181 [45]

ANSWER

The length of

$A'B'=14.04 \: units$

EXPLANATION

The object length given to us is,

$|AB|=10.8 \: units$

The scale factor of the dilation is,

$k = 1.3$

The image length can be calculated using the formula

$|A'B'| = k \times |AB|$

We substitute the given values into the formula to get,

$|A'B'| = 1.3\times 10.8$

We multiply out to obtain,

$|A'B'| = 14.04 \: units$

7 0

3 years ago

Someone please help!!!!!

Masteriza [31]

B and C by SSA (pls mark as brainliest)

5 0

3 years ago

IF A SUBSCRIPTION IS $499 PLUS 8% TAX FOR 30 DAYS, BUT IS BEING PRORATED FOR 7 DAYS, PLUS THERE IS A $10 OFF COUPON, WHAT'S THE

ELEN [110]

Answer:

Your final answer is $528.92

Step-by-step explanation: