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Advocard [28]
3 years ago
11

-0.5, 1 1/4, 0.25, 3/8 greatest to least decimal form

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0

-0.5, 0.25, 3/8, 1 1/4

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What is the slope of the line graphed below
Solnce55 [7]
Slope is 1/3

Equation of the line is:

y = 1/3x - 8
6 0
3 years ago
Graph f(x) =x and g(x) =-1/3x+2
Serjik [45]
Hello! I'll write the instructions to graph these functions.

f(x)=x
Technically, this function is y=x, so the slope would be 1. To graph this one, start at the origin (0,0) and move up one unit, and to the right one unit since this is a positive slope.

g(x)= -1/3x+2
First, plot a point at y=2 when x=0. 2 is your y-intercept. Your slope is negative, so the line will be decreasing. From your first point, head down 1 unit and to the right 3 units. Continue plotting points from the previous points.

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3 0
3 years ago
The 59th and 4th team of an Ap are - 61 and 64 respectively. Show that the common differences is - 2.5 and 23rd term is 16.5​
Mnenie [13.5K]

Answer:

See answers below

Step-by-step explanation:

T59 = a+58d = -61

T4 = a+3d = 64.

Subtract

58d-3d = -61-64

-55d = -125

d =125/55

d = 25/11

Get a;

From 2

a+3d = 64

a+3(25/11) = 64

a = 64-75/11

a = 704-75/11

a = 629/11

T23 = a+22d

T23 = 629/11+22(25/11)

T23 = 1179/11

3 0
3 years ago
R
TiliK225 [7]

Answer:

hviygkcgc fgx

Step-by-step explanation:

6 0
3 years ago
Which of the following statements must be true about the polynomial function f(x)? If 1+ the sqrt of 13 is a root of f(x), then
son4ous [18]

The correct answer is: if 1 + 13i is a root of f(x), then 1 - 13i is also a root of f(x).


In fact, every polynomial has real and/or complex solutions. If all solutions are real, we're good. But if not all of them are real, then the complex ones come in couple of conjugate solutions. Since 1 + 13i and 1 - 13i are conjugate complex numbers, if one of them is a solution, the other must be as well.

7 0
3 years ago
Read 2 more answers
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