<h3>Jason bought 20 stamps of $0.41 each and 8 postcards of $0.26 each.</h3>
<em><u>Solution:</u></em>
Let stamps be s and postcards be p
Given that,
The number of stamps was 4 more than twice the number of postcards
s = 4 + 2p -------- eqn 1
Jason bought both 41-cent stamps and 26-cent postcards and spent $10.28
41 cent = $ 0.41
26 cent = $ 0.26
Therefore,
0.41s + 0.26p = 10.28 --------- eqn 2
Substitute eqn 1 in eqn 2
0.41(4 + 2p) + 0.26p = 10.28
1.64 + 0.82p + 0.26p = 10.28
1.08p = 10.28 - 1.64
1.08p = 8.64
Divide both sides by 1.08
p = 8
Substitute p = 8 in eqn 1
s = 4 + 2(8)
s = 4 + 16
s = 20
Thus Jason bought 20 stamps and 8 post cards
Answer:
Distributive
Step-by-step explanation:
The 4y is distributed to the terms in parentheses.
Answer: a) 
b) 
c) 
Step-by-step explanation:
Since we have given that
There are green and yellow candies in each bag.
Bag A: Two thirds of the candies are yellow. What portion of the candies is green?
Part of yellow candies in bag A = 
Part of green candies in bag A would be
Bag B: 29 % of the candies are yellow. What portion of the candies is green?
Percentage of candies are yellow = 29%
Portion of candies are green is given by
Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?
Portion of yellow candies = 
Portion of green candies would be
Hence, a) b) c)
Answer:
the correct answer is 8.7
If you look at the graph of sin(n), you can notice that it oscillates every kpi/2 when k is odd. This oscillation proves that sin(n) diverges.
