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Anna [14]
3 years ago
7

Find the length of side x in the simplest radical form with a rational denominator​

Mathematics
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer:

Step-by-step explanation:

Recognize that this is a 30-60-90 triangle.  

Write and solve an equation of ratios:

 x         1

------ = ------- (which is the tangent of 30°)

√2       √3  

Then √3*x = √2, and so:

       √2

x = ----------

        √3

Rationalize this as follows:  

      √2*√3        √6

x = ------------- = ------

            3-            3

barxatty [35]3 years ago
3 0

Answer: 10√3 / 3

Step-by-step explanation:

cos 30 = 5 / x

x = 5 / cos 30

= 5 / √3 / 2

= 10 √3

= 10√3 / 3

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The isosceles trapezoid is part of an isosceles triangle with a 36° vertex angle. What is the measure of an acute base angle of
alexandr402 [8]
The answer is D) 72, 108

First you have to find out the measure of the two other angles in the triangle. Those two angles will be equivalent.

Because the sum of all three angles in a triangle is 180, you subtract 36 from it (180 - 36 = 144) then divide by 2 (144/2 = 72).

So, the two angles at the bottom of the triangle are each 72. Because those angles are supplementary to the angles at the top of the trapezoid, you subtract 72 from 180 (180 - 72 = 108).

108 + 108 = 216

The sum of all the angles in a trapezoid is 360, so subtract 216 from 360 (360 - 216 = 144) then divide by 2 (144/2 = 72)
6 0
3 years ago
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Answer:

1.(x+y)²

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6 0
3 years ago
Find the number of ways of arranging the numbers
Doss [256]

First of all, note that all integers are either 0,1, or 2 modulo 3 (if you're not familiar with this terminology, it means that every integer is either a multiple of 3, or it is 1 or 2 away from a multiple of 3).

So, we can think of our numbers as

\begin{array}{c|c}x&x\mod 3\\0&0\\1&1\\2&2\\3&0\\4&1\\5&2\\6&0\\7&1\\8&2\\9&0\end{array}

In order to make sure that the sum of any three adjacent numbers is divisible by 3, we have to make sure that any group of 3 three adjacent numbers contains a 0, a 1 and a 2. This is possible only if we arrange our 9 numbers in 3 groups of 3 numbers containing 0,1 and 2 exactly once, repeating always the same pattern.

For example, we could arrange our numbers following the pattern

0,1,2,0,1,2,0,1,2

or

2,0,1,2,0,1,2,0,1

We have 3!=6 possible patterns. Suppose for example that we choose the pattern

0,1,2,0,1,2,0,1,2

One possible way of following this pattern would be the arrangement

3,1,2,6,4,5,9,7,8

In fact, we substituted every '0' with a multiple of 3 (3, 6 or 9), every '1' with a number 1 away from a multiple of 3 (1, 4 or 7) and every '2' with a number 2 away from a multiple of 3 (2, 5 or 8).

This means that, once we fix a patter, we have 3 choices for the first 3 slots, 2 choices for the next 3 slots, and the final slot will be fixed. So, we have

3\cdot 3\cdot 3\cdot 2 \cdot 2 \cdot 2 = 216

possible ways of following a fixed pattern. Since the number of patterns was 6, we have

216\cdot 6 = 1296

possible arrangements.

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3 years ago
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