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Veronika [31]
3 years ago
5

Against the wind a small plane flew 715 miles in 2 hours and 10 minutes. The return trip took only 1 hour and 50 minutes. What w

as the speed of the​ wind? What was the speed of the plane in still​ air?
Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

  360 mi/h

Step-by-step explanation:

The speed for the outbound trip was ...

  speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h

The inbound speed was ...

  (715 mi)/(1 5/6 h) = 390 mi/h

The airspeed of the plane is the average of these two ground speeds, so is ...

  (330 +390)/2 = 360 . . . . mi/h

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Answer:

132\ in^{2} is closest to the total surface area of the box

Step-by-step explanation:

we know that

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SA=2B+PH

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we have

L=7\frac{3}{4}\ in=\frac{7*4+3}{4}=\frac{31}{4}\ in

W=3\frac{1}{4}\ in=\frac{3*4+1}{4}=\frac{13}{4}\ in

H=3\frac{7}{8}\ in=\frac{3*8+7}{8}=\frac{31}{8}\ in

<em>Find the area of the base B</em>

B=LW

B=(\frac{31}{4})(\frac{13}{4})=\frac{403}{16}\ in^{2}

<em>Find the perimeter of the base P</em>

P=2(L+W)

P=2(\frac{31}{4}+\frac{13}{4}))

P=2(\frac{44}{4})=22\ in

<em>Find the surface area</em>

SA=2(\frac{403}{16})+22(\frac{31}{8})

SA=(\frac{403}{8})+(\frac{682}{8})

SA=\frac{1,085}{8}=135.625\ in^{2}

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