The function can be solved as follows:
- f(6 + 4) = 25
- f(6) - f(4) = 20
- f(6 - 4) = 1
- f(6) - f(4) = 6
- f(6) . f(4) = 91
<h3>How to solve function?</h3>
f(x) = 3x - 5
Therefore, the function can be solved as follows:
f(6 + 4) = f(10) = 3(10) - 5 = 25
f(6) + f(4) = 3(6) - 5 + (3(4) - 5)
f(6) - f(4) = 13 + 7
f(6) - f(4) = 20
f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1
f(6) - f(4) = 3(6) - 5 - (3(4) - 5)
f(6) - f(4) = 18 - 5 - (12 - 5)
f(6) - f(4) = 13 - 7
f(6) - f(4) = 6
f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67
f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)
f(6) . f(4) = (18 - 5)(12 - 5)
f(6) . f(4) = (13)(7) = 91
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Answer:
the two numbers are 3 and 3.
1/5 of 3 is 0.6
1/5 of 6 is 1.2
Step-by-step explanation:
3 + 3 = 6
(1/5)3 = 0.6
(1/5)6 = 1.2
Answer:
A factor of 30 is chosen at random. What is the probability, as a decimal, that it is a 2-digit number?
The positive whole-number factors of 30 are:
1, 2, 3, 5, 6, 10, 15 and 30.
So, there are 8 of them. Of these, 3 have two digits. Writing each factor on a slip of paper, then putting the slips into a hat, and finally choosing one without looking, get that
P(factor of 30 chosen is a 2-digit number) = number of two-digit factors ÷ number of factors
=38=3×.125=.375 as a decimal number.
Answer:
12.5
Step-by-step explanation:
Answers:
After simplifying the following expression, the coefficient of the m^2 term will be <u> 13 </u>
The solution is <u> 13m^2 + 6mn^2 - 5nm^2 </u>
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Explanation:
Highlight all the terms that have m^2 in them and nothing else (so that means no variables of n or n^2)
You should highlight 3m^2, 16m^2 and -6m^2 as the three terms.
The coefficients 3, 16 and -6 combine to 3+16-6 = 13
Meaning that 3m^2+16m^2-6m^2 = 13m^2
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There are no other like terms that pair up.
The 6mn^2 and -5nm^2 are different because the exponent 2 is over a different letter each time. Put another way: mn^2 is not the same as nm^2
So we cannot combine 6mn^2-5nm^2. We leave it as is.
Overall, the entire expression simplifies to 13m^2 + 6mn^2 - 5nm^2
