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2 years ago

Please give the answer

Mathematics

1 answer:

sweet [91]2 years ago

5 0

The function can be solved as follows:

f(6 + 4) = 25
f(6) - f(4) = 20
f(6 - 4) = 1
f(6) - f(4) = 6
f(6) . f(4) = 91

<h3>How to solve function?</h3>

f(x) = 3x - 5

Therefore, the function can be solved as follows:

f(6 + 4) = f(10) = 3(10) - 5 = 25

f(6) + f(4) = 3(6) - 5 + (3(4) - 5)

f(6) - f(4) = 13 + 7

f(6) - f(4) = 20

f(6 - 4) = f(2) = 3(2) - 5 = 6 - 5 = 1

f(6) - f(4) = 3(6) - 5 - (3(4) - 5)

f(6) - f(4) = 18 - 5 - (12 - 5)

f(6) - f(4) = 13 - 7

f(6) - f(4) = 6

f(6.4) = f(24) = 3(24) - 5 = 72 - 5 = 67

f(6) . f(4) = (3(6) - 5 ) (3(4) - 5)

f(6) . f(4) = (18 - 5)(12 - 5)

f(6) . f(4) = (13)(7) = 91

learn more on function here: brainly.com/question/9390144

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3 years ago

Find the values of x and y in the diagram.

brilliants [131]

Answer:

x = 2, y = 6

Step-by-step explanation:

Δ WXY is equilateral ( 3 congruent angles ), then the sides are equal

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7 0

3 years ago

Luisa is planning a bridal shower for her best friend. At the party, she wants to serve 3 beverages, 3 appetizers, and 3 dessert

Vladimir79 [104]

Answer:

Luisa can pick the food and drinks to serve at the bridal shower in 15,615,600 different ways.

Step-by-step explanation:

Fundamental counting principle:

States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.

Also

The order in which the food and drinks are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Beverages:

3 from a set of 15. So

$B = C_{15,3} = \frac{15!}{3!12!} = 455$

Appetizers:

3 from a set of 10. So

$A = C_{10,3} = \frac{10!}{3!7!} = 120$

Desserts:

3 from a set of 13. So

$D = C_{13,3} = \frac{13!}{3!10!} = 286$

How many different ways can Luisa pick the food and drinks to serve at the bridal shower?

By the fundamental counting principle, as beverages, appetizers and desserts are independent:

$T = B*A*D = 455*120*286 = 15,615,600$

Luisa can pick the food and drinks to serve at the bridal shower in 15,615,600 different ways.

4 0

4 years ago

Yuto has a bag containing 3 red marbles 5 blue marbles 2 green marbles and 8 yellow Marbles what is the total number of possible

sleet_krkn [62]

Answer:

Step-by-step explanation:

Mission Information :

This question is incomplete this line is missing in the question " Rin reaches into the bag, pulls out a blue marble, and puts it in her pocket. Then Misaki reaches in and pulls out a marble. What is the total number of possible outcomes for Misaki’s marble"

Now coming to the solution ,

Given :

Red marbles=3

blue marbles=5

green marbles=2

yellow Marbles=8

Total number of outcomes can be determined by

=Red marbles + blue marbles + green marbles + yellow Marbles

$= 3\ +\ 5+2 +8=18$

As mention in the given question the Rin is pulling the 1 marble ,Now Total number of outcomes

$=18-1\\=17$

Therefore 17 is the correct answer

6 0

4 years ago