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Karo-lina-s [1.5K]

3 years ago

12

D=20-1.95c how would I work this out correctly

1 answer:

Amiraneli [1.4K]3 years ago

3 0

Umm is D represented by a number?

if it was, you would take D=20-1.95c subtract 20 from both sides, so you can isolate your variable, c

then divide both sides by -1.95 and you get

( D - 20 ) ÷ -1.95 = c

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White raven [17]

It’s 60 I think I’m not sure tho

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3 years ago

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What are significant figures?

scZoUnD [109]

Answer:

Significant Figures are the figures in a number that are meaningful and are digits with no zeros. Those zeros can be traced in a number like <em><u>“</u></em><em><u>3</u></em><em><u>2</u></em><em><u>0</u></em><em><u>”</u></em>, or <em><u>“</u></em><em><u>5</u></em><em><u>6</u></em><em><u>7</u></em><em><u>0</u></em><em><u>.</u></em><em><u>0</u></em><em><u>0</u></em><em><u>4</u></em><em><u>5</u></em><em><u>”</u></em>. Those zeros are not counted when counting the significant figures.

I hope you understand.

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3 years ago

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Levart [38]

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3 years ago

In the right triangle shown, AC = BCAC=BCA, C, equals, B, C and AB = 6AB=6A, B, equals, 6.

alexandr402 [8]

Answer:

$|AC|=|BC|=3\sqrt{2}$

Step-by-step explanation:

In a right triangle, the hypotenuse is always the longest side. Since AC = BC, AB is the Hypotenuse.

Using Pythagoras theorem

$|AB|=6,|AC|=|BC|\\|AB|^2=|AC|^2+|BC|^2\\6^2=2|AC|^2\\36=2|AC|^2\\18=|AC|^2\\|AC|=\sqrt{18}=3\sqrt{2} \\Therefore, |AC|=|BC|=3\sqrt{2}$

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3 years ago

Solve for w. <br><br> 1/3w + 5/6w - 2 = -w

Scorpion4ik [409]

Answer: $w=\frac{12}{13}$

Step-by-step explanation:

To solve for w, we want to isolate the variable.

$\frac{1}{3}w +\frac{5}{6}w-2=-w$ [add both sides by 2 and w]

$\frac{1}{3}w +\frac{5}{6}w+w=2$ [convert to same denominator]

$\frac{2}{6}w +\frac{5}{6}w+\frac{6}{6} w=2$ [add]

$\frac{13}{6} w=2$ [multiply both sides by 6/13]

$w=\frac{12}{13}$

Now we know that $w=\frac{12}{13}$ .

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