Answer:
62 and 63
Step-by-step explanation:
n + n + 1 = 125
2n + 1 = 125
2n = 124
n=62
You will make 1224-1000=224
then you will divide 224 by two it will be 112
you will add 112 to the less one
112+1000=1112
5(2+4m)=-2(5-10m)
10+20m=-10+20m
20m-20m=-10-10
m=-20
Answer: Here is the complete table, with the filled in values:
______________________________________________________________
Time (h) Distance (mi)
3 2
9 6
12 8
18 12
___________________________________________________
Explanation:
___________________________________________________
Let us begin by obtaining the "?" value; that is, the "distance" (in "mi.") ;
when the time (in "h") is "18" ;
___________________________________________________
12/8 = 18/?
Note: "12/8 = (12÷4) / (8÷4) = 3/2 ;
Rewrite: 3/2 = 18/? ; cross-multiply: 3*? = 2 * 18 ;
3*? = 36 ;
Divide each side by "3" ;
The "?" = 36/3 = 12 ;
So, 12/8 = 18/12 ;
The value: "12" takes the place for the "?" in the table for "distance (in "mi.);
when the "time" (in "h") is "18".
__________________________________________________________
Now, let us obtain the "? " value for the "distance" (in "mi.");
when the "time" (in "h") is: "9" .
12/8 = 9/? ; Solve for "?" ;
We know (see aforementioned) that "12/8 = 3/2" ;
So, we can rewrite: 3/2 = 9/? ; Solve for "?" ;
Cross-multiply: 3* ? = 2* 9 ; 3* ? = 18 ;
Divide each side by "3" ;
to get: "6" for the "?" value.
When the time (in "h") is "9", the distance (in "mi.") is "6" .
____________________________________________________
Now, to solve the final "?" value in the table given.
9/6 = ?/2 ; Note: We get the "6" from our "calculated value" (see above problem).
9/6 = (9÷3) / (6÷3) = 3/2 ;
So, we know that the "?" value is: "3" .
Alternately: 9/6 = ?/2 ;
Cross-multiply: 6*? = 2*9 ; 6 * ? = 18 ; Divide each side by "6" ;
to find the value for the "?" ;
"?" = 18/6 = "3" .
When the "distance" (in "mi.") is: "2" ; the time (in "h") is: "3" .
____________________________________________________
Here is the complete table—with all the values filled in:
____________________________________________________
<span>Time (h) Distance (mi)
____________________________________________________
3 2
9 6
12 8
18 12
____________________________________________________</span>
In calculus, we use derivatives to find the instantaneous rate of change at any point on a graph. To find the average rate of change, we just find the slope of the secant line that intercepts two points on the graph.
We find slope with the following equation:
In this case, we are looking for the slope from x = -1 to x = 1. We have both x values, so next we need the y values.
F(-1) = (-1)^2 - (-1) - 1 = 1
F(1) = (1)^2 - (1) - 1 = -1
Now plug in the x and y values to find the slope:
The answer is -1.
