Answer: Here is the complete table, with the filled in values: ______________________________________________________________ Time (h) Distance (mi) 3 2 9 6 12 8 18 12 ___________________________________________________
Explanation: ___________________________________________________ Let us begin by obtaining the "?" value; that is, the "distance" (in "mi.") ; when the time (in "h") is "18" ; ___________________________________________________
The value: "12" takes the place for the "?" in the table for "distance (in "mi.); when the "time" (in "h") is "18". __________________________________________________________ Now, let us obtain the "? " value for the "distance" (in "mi."); when the "time" (in "h") is: "9" .
12/8 = 9/? ; Solve for "?" ;
We know (see aforementioned) that "12/8 = 3/2" ;
So, we can rewrite: 3/2 = 9/? ; Solve for "?" ;
Cross-multiply: 3* ? = 2* 9 ; 3* ? = 18 ; Divide each side by "3" ; to get: "6" for the "?" value.
When the time (in "h") is "9", the distance (in "mi.") is "6" . ____________________________________________________ Now, to solve the final "?" value in the table given.
9/6 = ?/2 ; Note: We get the "6" from our "calculated value" (see above problem).
9/6 = (9÷3) / (6÷3) = 3/2 ;
So, we know that the "?" value is: "3" .
Alternately: 9/6 = ?/2 ;
Cross-multiply: 6*? = 2*9 ; 6 * ? = 18 ; Divide each side by "6" ; to find the value for the "?" ; "?" = 18/6 = "3" .
When the "distance" (in "mi.") is: "2" ; the time (in "h") is: "3" . ____________________________________________________ Here is the complete table—with all the values filled in: ____________________________________________________
Basically you enter this equation into a graphing calculator and see which x and y value match and those are your points . Or you can substitute values in for x by isolating y by itself
In a compound interest equation, the first value is the initial investment. In this case, it would be 5000. After the 5000, you would enter the rate that is being used.
