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IceJOKER [234]
4 years ago
15

Find the circumference of the following circle. Use 3.14 for π. Round to the nearest hundredth, if necessary.

Mathematics
1 answer:
Y_Kistochka [10]4 years ago
5 0

Answer:

18π cm

Step-by-step explanation:

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PLZ HELP ME ASAP W THIS !!!
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Answer:

(2x+3) x (x-7)

Step-by-step explanation:

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3 years ago
What is 13 to the power of 200
ser-zykov [4K]

Answer:

6.147103e+222

8 0
3 years ago
Read 2 more answers
Statistics Probability
andriy [413]

Answer:

Explained below.

Step-by-step explanation:

Denote the variable as follows:

M = male student

F = female student

Y = ate breakfast

N = did not ate breakfast

(a)

Compute the probability that a randomly selected student ate breakfast as follows:

P(Y)=\frac{n(Y)}{N}\\\\=\frac{198}{330}\\\\=0.60

(b)

Compute the probability that a randomly selected student is female and ate breakfast as follows:

P(F\cap Y)=\frac{n(F\cap Y)}{N}\\\\=\frac{121}{330}\\\\=0.367

(c)

Compute the probability a randomly selected student is male, given that the student ate breakfast as follows:

P(M|Y)=\frac{n(M\cap Y)}{n(Y)}\\\\=\frac{77}{198}\\\\=0.389

(d)

Compute the probability that a randomly selected student ate breakfast, given that the student is male as follows:

P(Y|M)=\frac{n(Y\cap M)}{n(M)}\\\\=\frac{77}{154}\\\\=0.50

(e)

Compute probability of the student selected "is male" or "did not eat breakfast" as follows:

P(M\cup N)=P(M)+P(N)-P(M\cap N)\\\\=\frac{n(M)}{N}+\frac{n(N)}{N}-\frac{n(M\cap N)}{N}\\\\=\frac{n(M)-n(N)-n(M\cap N)}{N}\\\\=\frac{154+132-77}{330}\\\\=0.633

(f)

Compute the probability of "is male and did not eat breakfast as follows:

P(M\cap N)=\frac{n(M\cap N)}{N}\\\\=\frac{77}{330}\\\\=0.233

4 0
3 years ago
(Please Help For Examination) A sweet stall was placing order for making cardboard boxes for packing their sweets. Two sizes of
frozen [14]
Answer: Rs 2,184

Explanation:

1) The statement is incomplete. The complete statement contains the information of the dimensions of both bigger and smaller cardboard boxes.

2) The dimesions of bigger cardboard boxes are 25cm * 20 cm * 5 cm

3) The dimensions of smaller cardboard boxes are 15 cm * 12 cm * 5cm

4) For bigger cardboard boxes:

length, l = 25 cm
width, w = 20 cm
height, h = 5 cm

surface of each bigger carboard box = 2 [ l*w + l*h + w*h] = 2 [25*20 + 25*5 + 20*5] cm^2 = 1450 cm^2

total surface of 250 bigger cardboard boxes = 250 * 1450 cm^2 = 3625,500 cm^2

5% of the total surface area extra = 362,500cm^2 * 5 / 100 = 18,125 cm^2

Total area for bigger cardboard boxes= 362,500 cm^2 +  18,125 cm^2 = 380,625 cm^2

5) Smaller cardboard boxes

length, l = 15 cm
width, w = 12 cm
height, h =  5 cm

surface of each smaller cardboard box = 2 [l*w + l*h + w*h] = 2 [ 15*12 + 15 * 5 + 12 * 5] cm^2 = 630 cm^2

total surface of 250 smaller cardboard boxes = 250 * 630 cm^2 = 157,500 cm^2

5 % extra = 157,500 cm^2 * 5 / 100 = 7,875 cm^2

total area for smaller cardboard boxes = 157,500 cm^2 + 7,875 cm^2 = 165,375 cm^2

6) total area of cardboard required  = 380,625 cm^2 + 165,375 cm^2 = 546,000 cm^2

7) Cost of cardboard required

unit cost per area * total area = (Rs 4 / 1000cm^2) * 546,000 cm^2 = Rs 2,184.

Answer: Rs 2,184
7 0
4 years ago
What is the absolute value of negative 4 minus 9 i?
vladimir2022 [97]

Answer: 13

Step-by-step explanation:

-4 - 9 = -13

4 0
3 years ago
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