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-Dominant- [34]
3 years ago
8

7,801 + = 4,890 what is the number

Mathematics
1 answer:
zysi [14]3 years ago
4 0
You subtract the numbers 7,801 and 4890

The answer is 2,911
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(6+√25)/(4-√3) can be written in the form of (2+s√3)/13 where r and s are both integers what are the values of r and s
cestrela7 [59]

Answer:

r = 33

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Step-by-step explanation:

Given expression is \frac{6+\sqrt{27}}{4-\sqrt{3}}.

Multiply numerator and denominator with the conjugate of (4 - √3).  

\frac{(6+\sqrt{27})(4+\sqrt{3})}{(4-\sqrt{3})(4+\sqrt{3})}

= \frac{4(6+\sqrt{27})+\sqrt{3}(6+\sqrt{27})}{4^{2}-(\sqrt{3})^2}

= \frac{24+4\sqrt{27}+6\sqrt{3}+\sqrt{81})}{16-3}

= \frac{24+12\sqrt{3}+6\sqrt{3}+\sqrt{81})}{16-3}

= \frac{24+18\sqrt{3}+9}{13}

= \frac{33+18\sqrt{3}}{13}

Now compare this expression with \frac{r+s\sqrt{3} }{13}

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3 years ago
For what real values of does the quadratic 12x^2+kx+27=0 have nonreal roots
bija089 [108]

Answer:

k<±36

Step-by-step explanation:

Δ<0 (no real roots)

b²-4ac<0

k²-4x12x27<0

k²-1296<0

k²<1296

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3 years ago
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