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chubhunter [2.5K]
3 years ago
15

Seven decreased by three times a number is forty,please help

Mathematics
2 answers:
GREYUIT [131]3 years ago
5 0
7 - 3 = 4

4 x .... = 40

4 x 10 = 40
Nonamiya [84]3 years ago
4 0
Hello, 

x= the number
3x= three times the number

seven decreased by three times a number is forty, then:

7-3x=40
-3x=33
x=-11

Answer: the number is -11
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Katie gives Maggie half of her pencils. Maggie keeps 5 pencils and gives the rest to Jamil. A. Write an expression for the numbe
Alexandra [31]

Here's what I mean when I write <em>x/</em><em>2</em><em> </em><em>JUST </em><em>IN </em><em>CASE.</em>

а.

Let the total number of pencils be x, then this implies that Maggie received <em>x/</em>2 pencils from Katie. Maggie keeps 5 and give the rest to Jamil, this means

that Jamil receives

<em>x/</em>2-5 pencils.

b. Expression of pencils given to Jamil is: <em>x/</em>2-5

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Maggie gives 3 pencils to Jamil.

c. Expression of pencils given to Jamil is: x/2-5 to

Equate this expression with 1 to form an equation and solve for <em>x</em> all, the total

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Katie had 12 pencils if Jamil received 1 pencil.

RESULT

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b. Maggie gives 3 pencils to Jamil.

c. Katie had 12 pencils if Jamil received 1 pencil.

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2 years ago
Find the taylor polynomial t3(x) for the function f centered at the number
inysia [295]

Answer:

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3

Step-by-step explanation:

We are given that

f(x)=7tan^{-1}(x)

a=1

T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}

Substitute n=3 and a=1

t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}

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Where tan^{-1}(1)=\frac{\pi}{4}

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Using the formula

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f''(x)=\frac{-14x}{(1+x^2)^2}

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(uv)'=u'v+v'u

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f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}

Substitute the values

t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3

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