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Nikitich [7]
3 years ago
12

Write out the first 5 outpouts of g(x)=2^x starting with G(1). If only you knew that the value of g(15) how would you determine

g(16)?
Mathematics
1 answer:
gtnhenbr [62]3 years ago
4 0

The first 5 outputs are:

\begin{array}{c|c}x&2^x\\1&2\\2&4\\3&8\\4&16\\5&32\end{array}

As you can see, the outputs keep doubling each time we increment x by 1.

This can be written formally, observing that if you know the value of 2^x, the next value will be

2^{x+1}=2^x\cdot 2

So, again, we've shown that the next value is twice the previous one, so you have

g(16)=2g(15)

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PLS help me Order four and seven tenths repeating, negative four and eight ninths, 490%, and −4.9 from least to greatest.
Digiron [165]

The order from least to greatest negative four and seven tenths repeating, negative four and eight ninths, 490%, and −4.9 from least to greatest is; option A

  • −4.9,
  • negative four and eight ninths
  • four and seven tenths repeating
  • 490%,

<h3>Ascending order</h3>

four and seven tenths repeating

= 4.77777777

negative four and eight ninths

= -4 8/9

= -4.888888888888888

490%

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= 4.9

−4.9

Rearranging from least to greatest (ascending order)

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Learn more about ascending order;

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