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Nikitich [7]
3 years ago
12

Write out the first 5 outpouts of g(x)=2^x starting with G(1). If only you knew that the value of g(15) how would you determine

g(16)?
Mathematics
1 answer:
gtnhenbr [62]3 years ago
4 0

The first 5 outputs are:

\begin{array}{c|c}x&2^x\\1&2\\2&4\\3&8\\4&16\\5&32\end{array}

As you can see, the outputs keep doubling each time we increment x by 1.

This can be written formally, observing that if you know the value of 2^x, the next value will be

2^{x+1}=2^x\cdot 2

So, again, we've shown that the next value is twice the previous one, so you have

g(16)=2g(15)

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Maria has $50 in a savings account in week 1. She plans on depositing $8
enot [183]

Answer:

466

Step-by-step explanation:

50 + 8*52 = 466

4 0
3 years ago
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-3x+4y=-4 -2x+5y=9<br>solve the following system of equations
Vesnalui [34]

the answer is x= 8, and y=5

3 0
3 years ago
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Solve this equation: y-3x+15=10
Jlenok [28]

Answer:

10=10

Step-by-step explanation:

y-3x+15=10

y=3x-15+10

y=3x-5

subtitute y=3x-5 in the above equation:

3x-5-3x+15=10 (3x will be eliminated with -3x)

-5+15=10

10=10

(i hope this is the way you want the answer but at least I think it is correct)

3 0
3 years ago
A random sample of 400 voters in a certain city are asked if they favor an additional 4% gasoline tax to provide badly needed re
Norma-Jean [14]

Answer:

A) α = 0.04136

B) β = 0.00256

Step-by-step explanation:

We are given;

Sample size; n = 400

Proportion; p = 60% = 0.6

Formula for mean is;

μ = np

μ = 400 × 0.6 = 240

Standard deviation is given by;

σ = √npq

Where q = 1 - p = 1 - 0.6 = 0.4

σ = √(400 × 0.6 × 0.4)

σ = √96

σ = 9.8

A) our null hypothesis is at p = 0.6

Probability of making a type I error means we reject the null hypothesis when it is true.

This can be expressed in reference to the question as;

α = P(x < 220) + P(x > 260) all at p = 0.6

Now,

P(x < 220) = z = (x¯ - μ)/σ = (220 - 240)/9.8 = -2.04

Also;

P(x > 260) = z = (260 - 240)/9.8 = 2.04

Now, from z-distribution table probability of a z-score of -2.04 is 0.02068.

Also, probability of z-score of 2.04 is (1 - P(z < 2.04) = 1 - 0.97932 = 0.02068

Thus;

α = 0.02068 + 0.02068

α = 0.04136

B) Type II error occurs when we fail to reject the null hypothesis even though it's false.

In this case our alternative hypothesis is at p = 48% = 0.48

Thus;

μ = np

μ = 400 × 0.48 = 192

Standard deviation is given by;

σ = √npq

Where q = 1 - p = 1 - 0.48 = 0.52

σ = √(400 × 0.48 × 0.52)

σ = √99.84

σ = 9.992

Type II error would be given by;

β = [((x1¯ - μ)/σ) < z > ((x2¯ - μ)/σ)]

β = [((220 - 192)/9.992) < z > ((260 - 192)/9.992)]

β = (2.8 < z > 6.81)

Rearranging this gives us;

β = P(z < 6.81) - P(z < 2.8)

From z-distribution tables, we have;

β = 1 - 0.99744

β = 0.00256

3 0
2 years ago
Give an example of an odd function and explain algebraically why it is odd.
NARA [144]
F(x) = x^3
f(-x) = (-x)^3 = -x^3
but if u factor out the negative then
f(-x) = -(x)^3
therefore it is an odd function because f(-x) = -f(x)
4 0
3 years ago
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