All categories

3 years ago

What is this shape???

Mathematics

1 answer:

Alex17521 [72]3 years ago

3 0

The answer to that one is A. Isosceles trapezoid

You might be interested in

Please help I’m confused

jek_recluse [69]

Help with? There is no question.

6 0

3 years ago

Read 2 more answers

Solve the linear equation. 3x = 24 x = ?

trapecia [35]

Answer:

3x =24

x = 24 -3

x = 21 (ans)

6 0

3 years ago

I need help please

nlexa [21]

Answer:

Step-by-step explanation:

No she is not correct because we dont have only one angle angle G is 90.

So we can easily find the angle D

180-(90+41) =49

7 0

2 years ago

The lengths of the bases of the right trapezoid are 9 cm and 18 cm. The length of a longer leg is 15 cm. Find the area of the tr

finlep [7]

Firstly, we will draw figure

now, we will draw a altitude from B to DC that divides trapezium into rectangle and right triangle

because of opposite sides of rectangle ABMD are congruent

so,

DM=AB=9

CM=CD-DM

CM=18-9

CM=9

now, we can find BM by using Pythagoras theorem

$BM=\sqrt{BC^2-CM^2}$

now, we can plug values

we get

$BM=\sqrt{15^2-9^2}$

$BM=12$

now, we can find area of trapezium

$A=\frac{1}{2} (AB+CD)*(BM)$

now, we can plug values

and we get

$A=\frac{1}{2} (9+18)*(12)$

$A=162cm^2$

so, area of of the trapezoid is $162cm^2$ ..........Answer

6 0

3 years ago

Please hurry i don't have much time left!

quester [9]

Answer:

Check below

Step-by-step explanation:

That's too bad you haven't attached a rectangle.

Here's an example, with the data you've typed in.

1) When we dilate a rectangle we either grows it or shrink it through a scale factor.

Check the first picture below.

The New Dilated Rectangle A'B'C'D' will follow its coordinates, when the <u>Center of Dilation is at its origin(Middle):</u>

$D_{A'B'C'D'}=\frac{1}{2}(x,y)$

2) But In this question, <u>B is the center of Dilation</u>. So, Since B is the Dilation Point B=B' . And More importantly:

$\bar{AB}=\frac{1}{2}\bar{A'B'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\\bar{AC}=\frac{1}{2}\bar{A'C'}\\\bar{CD}=\frac{1}{2}\bar{C'D'}\\$

3) So check the pictures below for a better understanding.

6 0

3 years ago

Read 2 more answers