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ludmilkaskok [199]
3 years ago
7

Data on the weights​ (lb) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is

summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed​ populations, and do not assume that the population standard deviations are equal. Complete parts​ (a) and​ (b) below. Use a 0.010.01 significance level for both parts. Diet Regular muμ mu 1μ1 mu 2μ2 n 3535 3535 x overbar x 0.794940.79494 lb 0.805090.80509 lb s 0.004490.00449 lb 0.007570.00757 lb a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative​ hypotheses
Mathematics
1 answer:
OLga [1]3 years ago
7 0

Answer:

reject the null hypothesis. There is sufficient evidence to support the claim that the cans of diet soda have mean weights that are lower than the mean weight for the regular soda.

Step-by-step explanation:

I hope this helps, I'm in 11th grade and I'm pretty sure the answer is correct. Good Luck!!!

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x = 24
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Explanation:

1) Since, the given triangle is a right triangle, and you have both an angle and the hypotenuse length, you can use some trigonometric ratios to find the variables.

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y: opposite length to angle 30°

3) sine ratio:

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Step-by-step explanation:

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Question Progress
mixas84 [53]

Answer:

Please check the attached figure!

Step-by-step explanation:

Part a)

Point A is located at the x-coordinate x=-4 and y-coordinate y=1.

Hence, the coordinates of point A = (-4, 1)

Part b)

Point B(3, -2) has been plotted and is shown in the attached figure.

It is clear from the attached diagram that point B is located at the x-coordinate x=3 and y-coordinate y=-2. Hence, the coordinates of point B = (3, -2)

Part C)

Point C has the same x-coordinate as point A i.e. x=-4 and the same y-coordinate as point B i.e. y=-2.

Hence, the coordinates of point C = (-4, -2). Point C is also plotted as shown in the diagram.

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