F(gx)
f(-x-4) = 2(-x-4) + 3
F(-x-4)= -2x-8+3
F(-x-4)= -2x-5
G(fx)
G(2x+3)= -(2x+3) -4
G(2x+3)= -2x-3-4
G(2x+3)= -2x-7
F(hx)
F(x^2)=2x^2+3
H(fx)
H(2x+3)= (2x+3)^2
H(2x+3)= (2x^2) + 2(2x)(3)+3^2
H(2x+3)= 4x^2+12x+9
[I think I messed up with the last one. I didn’t know how to get the correct answer for that. Sorry ]
The answer will be 0 which is the degree for f.
Hope this helps!
Answer:
D,x < 36 and x > 0, negative number cannot be in sq.root
Answer:
730·t
Step-by-step explanation:
365*2= 730
Hope this helps