The answer i think is. If<span> the </span>length<span> of the </span>table<span> is </span>18 ft more than<span> the </span>width<span>, </span>x, which - 1447102. ... Thearea<span> of the </span>conference table<span> in </span>Mr<span>. </span>Nathan's office must<span> be </span>no more than 175 ft2<span> ... Therefore, the</span>interval<span> 0 < </span>x<span> ≤ 7 represents the possible widths</span>
219 divided by 8=27.35
27x8=216
219-216=3
Matthew can make 27 packages.
3 pens will be left over.
Please mark Brainelist
3y = 5x + 30
y + 5x = 50 .......(1)
3y - 5x = 30 .....(2) - rearranging the first equation.
Add (1) and (2):-
4y = 80
y = 20
Now plug y = 20 into equation (1):-
20 + 5x = 50
5x = 30
x = 6
The 2 numbers are 6 and 20.
