Answer:
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Step-by-step explanation:
The scores of two groups can be compared using coefficient of variation;
Coefficient of variation (C.V.) = (Standard Deviation/ Mean) × 100%;
For Data set 1;
Standard deviation = 3.6
Mean = 35.3
C.V. = (3.6/35.3) × 100%;
= 10.19%
For Data set 2;
Standard deviation = 0.5
Mean = 34.1
C.V. = (0.5/34.1) × 100%;
= 1.46%
To learn more about coefficient of variation, visit: brainly.com/question/24131744
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You have to pick at least one even factor from the set to make an even product.
There are 3 even numbers to choose from, and we can pick up to 3 additional odd numbers.
For example, if we pick out 1 even number and 2 odd numbers, this can be done in

ways. If we pick out 3 even numbers and 0 odd numbers, this can be done in

way.
The total count is then the sum of all possible selections with at least 1 even number and between 0 and 3 odd numbers.

where we use the binomial identity

Answer:
negative
Step-by-step explanation: