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nordsb [41]
3 years ago
15

Suryana bought 16 watches for rs 16000. At what rate should he sell the watches to gain rs 3200?​

Mathematics
2 answers:
dangina [55]3 years ago
8 0

Answer:

Step-by-step explanation:

So if 16 watches is 16000 rs, then if you want to make 3200 more rs, your total from 16 watches should be 19200 (which is 16000+3200)

so the rate per watch should be 19200/16 = 1200

So it should be 1200rs/watch is the rate

faltersainse [42]3 years ago
5 0

Answer:

So if 16 watches is 16000 rs, then if you want to make 3200 more rs, your total from 16 watches should be 19200 (which is 16000+3200)

so the rate per watch should be 19200/16 = 1200

So it should be 1200rs/watch is the rate

Step-by-step explanation:

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Which of the following represents the relationship between the circumference, c, and diameter, d, of any circle?
Usimov [2.4K]

Given:

Circumference of a circle = C

Diameter of a circle = d

To find:

The relationship between the circumference, c, and diameter, d, of any circle.

Solution:

We know that, circumference of a circle is

C=2\pi r

It can be written as

C=(2r)\pi

C=d\pi         [\because d=2r]

On dividing both sides by d, we get

\dfrac{C}{d}=\pi

Therefore, the correct option is (F).

6 0
2 years ago
Drag the expressions to the correct functions. Not all expressions will be used.
postnew [5]

The function composition exists an operation " ∘ " that brings two functions f and g, and has a function h = g ∘ f such that h(x) = g(f(x)).

Let the functions be f(x) = 4x² + 1 and g(x) = x² - 3

The correct answer is (f o g)(x) = 4x⁴ - 96x + 37 and

(g o f)(x) = 16x⁴ + 8x² - 2.

<h3>What is composition function?</h3>

The function composition exists an operation " ∘ " that brings two functions f and g, and has a function h = g ∘ f such that h(x) = g(f(x)). In this operation, the function g exists used for the outcome of applying the function f to x.

Given:

f(x) = 4x² + 1 and g(x) = x² - 3

a) (f o g)(x) = f[g(x)]

f[g(x)] = 4(x² - 3)² + 1

substitute the value of g(x) in the above equation, and we get

    = 4(x⁴ - 24x + 9) + 1

simplifying the above equation

    = 4x⁴ - 96x + 36 + 1

    = 4x⁴ - 96x + 37

(f o g)(x) = 4x⁴ - 96x + 37

b) (g o f)(x) = g[f(x)]

substitute the value of g(x) in the above equation, and we get

g[f(x)] = (4x² + 1)²- 3

      = 16x⁴ + 8x² + 1 - 3

simplifying the above equation

      = 16x⁴ + 8x² - 2

(g o f)(x) = 16x⁴ + 8x² - 2.

Therefore, the correct answer is (f o g)(x) = 4x⁴ - 96x + 37 and

(g o f)(x) = 16x⁴ + 8x² - 2.

To learn more about the function refer to:

brainly.com/question/26709985

#SPJ9

7 0
2 years ago
Someone plz answer this for me
padilas [110]
Cos theta = base /perp = sqrt(13)/7 =0.515
4 0
3 years ago
G(x)=-x^2/4 +7<br> Over which interval does g have a negative average rate of change?
Sholpan [36]

Answer:

x = 49

Step-by-step explanation:

1- Substitute g ( x ) = 0

Reduce

g ( x ) = - x 2/4 + 7

2- Move the variable to the left

0 = - x 1/2 + 7

3- Simplify the equation

x 1/2 = 7

4- Simplify Evaluate

( x 1/2 ) ² = 7²

5- Check the solution

x= 49

6- Simplify

0= - 49 2/4 + 7

7- x = 49 is a solution

0 = 0  

4 0
3 years ago
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Firdavs [7]

Answer:

Domain: All real numbers

Range: y\leq -3

Step-by-step explanation:

The domain is the set of all x values. The quadratic equation continue to operate over all x-values in both directions. The domain is all real numbers.

The range is the set of all y-values. Here the quadratic begins at -3 and continues in a downward direction forever. Then range is y\leq -3

6 0
3 years ago
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